我正在使用Knuth-Fisher-Yates算法在Windows窗体上显示一个混洗的字符串项数组。我没有得到任何重复,这是我试图实现的,但是,它只吐出数组的13个元素中的12个。如何让它显示数组的所有13个元素?这是我的代码:
private void FormBlue1_Load(object sender, EventArgs e)
{
// set the forms borderstyle
this.FormBorderStyle = FormBorderStyle.Fixed3D;
// create array of stationOneParts to display on form
string[] stationOneParts = new string[13];
stationOneParts[0] = "20-packing";
stationOneParts[1] = "5269-stempad";
stationOneParts[2] = "5112-freeze plug";
stationOneParts[3] = "2644-o'ring";
stationOneParts[4] = "5347-stem";
stationOneParts[5] = "4350-top packing";
stationOneParts[6] = "5084-3n1 body";
stationOneParts[7] = "4472-packing washer";
stationOneParts[8] = "3744-vr valve o'ring";
stationOneParts[9] = "2061-packing spring";
stationOneParts[10] = "2037-packing nut";
stationOneParts[11] = "2015-latch ring";
stationOneParts[12] = "stem assembly";
Random parts = new Random();
// loop through stationOneParts using a Swap method to shuffle
labelBlueOne.Text = "\n";
for (int i = stationOneParts.Length - 1; i > 0; i--)
{
int j = parts.Next(i + 1);
Swap(ref stationOneParts[i], ref stationOneParts[j]);
// display in a random order
labelBlueOne.Text += stationOneParts[i] + "\n";
}
}
private void Swap(ref string firstElement, ref string secondElement)
{
string temp = firstElement;
firstElement = secondElement;
secondElement = temp;
}
答案 0 :(得分:2)
您无法访问第一个元素。 for(int i = stationOneParts.Length - 1; i> = 0; i - )。
答案 1 :(得分:2)
当您使用交换项目的循环显示文本时,您将不会显示最后一项,因为它永远不会自行交换。
只显示循环后的最后一项:
labelBlueOne.Text += stationOneParts[0] + "\n";
或者,您可以显示循环之外的所有项目:
for (int i = stationOneParts.Length - 1; i > 0; i--) {
Swap(ref stationOneParts[i], ref stationOneParts[parts.Next(i + 1)]);
}
labelBlueOne.Text = "\n" + String.Join("\n", stationOneParts);
答案 2 :(得分:1)
将循环条件更改为i >= 0
。
答案 3 :(得分:1)
最简单的方法:
Random rnd = new Random();
var stationOneParts = new List<string>{
"20-packing",
"5269-stempad",
"5112-freeze plug",
"2644-o'ring",
"5347-stem",
"4350-top packing",
"5084-3n1 body",
"4472-packing washer",
"3744-vr valve o'ring",
"2061-packing spring",
"2037-packing nut",
"2015-latch ring",
"stem assembly"}.OrderBy(s => rnd.Next());
labelBlueOne.Text = string.Join(Environment.NewLine, stationOneParts);
答案 4 :(得分:0)
既然你提到C#4.0,为什么不写C#-ish?
using System.Linq;
// ...
var stationOneParts = new [] { "20-packing",
"5269-stempad",
"5112-freeze plug",
"2644-o'ring",
"5347-stem",
"4350-top packing",
"5084-3n1 body",
"4472-packing washer",
"3744-vr valve o'ring",
"2061-packing spring",
"2037-packing nut",
"2015-latch ring",
"stem assembly" };
Random rand = new Random();
stationOneParts = stationOneParts
.Distinct() // see subject: '... without duplicates'
.Select(i => new { i, key=rand.Next() })
.OrderBy(p => p.key)
.Select(p => p.i)
.ToArray();