Configuring JPA(Hibernate) with Tomcat 8.0

时间:2016-02-12 19:24:50

标签: java hibernate tomcat jpa provider

I have problem with configuring Tomcat 8.0 with JPA using Hibernate as a provider in Eclipse. When i tried to use DataSource Annotation and standard JDBC way to connect to DB, the connection is ok but when i try to use Hibernate and i get an exception about there is no provider for my PU. I tried to move hibernate libs to many directories (web-inf/lib, apache TC library) but i still get the same exception. I think the data source is configured properly. Below i add my configured files.

web.xml

<?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1"> <display-name>HibernateTest</display-name> <resource-ref> <description>DB Connection</description> <res-ref-name>jdbc/HibernateTest</res-ref-name> <res-type>javax.sql.DataSource</res-type> <res-auth>Container</res-auth> </resource-ref> <welcome-file-list> <welcome-file>index.html</welcome-file> <welcome-file>index.htm</welcome-file> <welcome-file>index.jsp</welcome-file> <welcome-file>default.html</welcome-file> <welcome-file>default.htm</welcome-file> <welcome-file>default.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>/faces/*</url-pattern> </servlet-mapping> <context-param> <description>State saving method: 'client' or 'server' (=default). See JSF Specification 2.5.2</description> <param-name>javax.faces.STATE_SAVING_METHOD</param-name> <param-value>client</param-value> </context-param> <context-param> <param-name>javax.servlet.jsp.jstl.fmt.localizationContext</param-name> <param-value>resources.application</param-value> </context-param> <listener> <listener-class>com.sun.faces.config.ConfigureListener</listener-class> </listener> </web-app>

persistence.xml

<?xml version="1.0" encoding="UTF-8"?> <persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd"> <persistence-unit name="HibernateTest" transaction-type="JTA"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <jta-data-source>jdbc/HibernateTest</jta-data-source> <properties> <property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQLDialect"/> <property name="hibernate.hbm2ddl.auto" value="create-drop" /> </properties> </persistence-unit> </persistence> context.xml in tomcat(only fragment)

<WatchedResource>WEB-INF/web.xml</WatchedResource> <Resource name="jdbc/HibernateTest" auth="Container" type="javax.sql.DataSource" maxActive="100" maxIdle="30" maxWait="10000" username="admin" password="admin" driverClassName="org.postgresql.Driver" url="jdbc:postgresql://localhost:5432/Hibernate"/> <WatchedResource>${catalina.base}/conf/web.xml</WatchedResource>

public TestServlet() {
    super();
    // TODO Auto-generated constructor stub
}

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    EntityManagerFactory emf = Persistence.createEntityManagerFactory("HibernateTest");
    EntityManager em = emf.createEntityManager();

    em.close();
    emf.close();

}

} `

1 个答案:

答案 0 :(得分:0)

Since Tomcat is a servlet container (as opposed to a full blown J2EE application server), JTA doesn't come with it. If you want to use JTA in Tomcat, you have to drop in an implementation of your choice.