Question

我正在处理这个简单的任务，我需要使用2个while循环。第一个while循环检查小时数是否小于0，如果是，则循环应该继续询问用户。这是我的代码：

hours = float(input('Enter the hours worked this week: '))

count = 0
while (0 > hours):
    print ('Enter the hours worked this week: ')
    count = count + 1

pay = float(input('Enter the hourly pay rate: '))
while (0 > pay):
    print ('Enter the hourly pay rate: ')
    count = count + 1

total_pay = hours * pay

print('Total pay: $', format(total_pay, ',.2f'))

Answer 1

break正是您要找的。

x = 100
while(True):
    if x <= 0:
        break
    x -= 1
print x # => 0

至于你的例子，似乎没有任何东西会导致中断。例如：

hours = float(input('Enter the hours worked this week: '))

count = 0

while (0 > hours):
    print ('Enter the hours worked this week: ')
    count = count + 1

您根本没有编辑hours变量。这只会继续打印"Enter the hours worked this week: "并无限增加count。我们需要知道提供更多帮助的目标是什么。

Answer 2

您可以使用break或将条件设为false来退出循环。

在您的情况下，您接受用户的输入，如果hours < 0，则打印提示并更新计数，但您不会更新小时数。

while (0 > hours):
    print ('Enter the hours worked this week: ')
    count = count + 1

应该是：

while (0 > hours):
    hours = float(input('Enter the hours worked this week: '))
    count = count + 1

同样适用于付款：

while (0 > pay):
    pay = float(input('Enter the hourly pay rate: '))
    count = count + 1

Answer 3

好吧，另一个答案向您展示了如何摆脱while循环，但您还没有分配付费和小时变量。您可以使用内置输入功能来获取用户提供给程序的内容

hours = float(input('Enter the hours worked this week: '))

count = 0
while (0 > hours):
    hours = input('Enter the hours worked this week: ')
    count = count + 1

pay = float(input('Enter the hourly pay rate: '))
while (0 > pay):
    pay =  input('Enter the hourly pay rate: ')
    count = count + 1

total_pay = hours * pay

print('Total pay: $', format(total_pay, ',.2f'))

如何在python中退出while循环？

3 个答案: