我有一个包含四种不同方法的代码(下图没有图片)并创建了一个菜单供用户选择他们想要选择的方法。
除非用户输入5,否则如何将方法循环到菜单屏幕的位置?
import java.util.Scanner;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.PrintWriter;
public class ReactionAnalysis {
public static void main (String [] args) throws FileNotFoundException
{
/// Menu Screen
System.out.println("What would you like to do?");
System.out.println("1: Get the score of a word");
System.out.println("2: Get the average score of words in a file (one word per line)");
System.out.println("3: Find the highest/lowest scoring words in a file");
System.out.println("4: Sort words from a file into positive.txt and negative.txt");
System.out.println("5: Exit the program");
Scanner in = new Scanner(System.in);
System.out.println("Enter a number 1-5");
int numberChoice = in.nextInt();
////
while (numberChoice != 5)
{
if (numberChoice == 1)
{
String methodOne = methodOne();
System.out.println(methodOne);
}
else if (numberChoice == 2)
{
String methodTwo = methodTwo();
System.out.println(methodTwo);
}
else if (numberChoice == 3)
{
String methodThree = methodThree();
System.out.println(methodThree);
}
else if (numberChoice == 4)
{
String methodFour = methodFour();
System.out.println(methodFour);
}
}
}
}
现在,在我完全完成其中一个步骤之后,它只是重复了这一步骤。我需要它来完成步骤,然后返回菜单,并重复,除非在菜单中输入5。
答案 0 :(得分:0)
很抱歉格式化,只需复制粘贴大部分代码:我将循环移动到顶部,并将int初始化为0,因此它至少会运行一次。
import java.util.Scanner;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.PrintWriter;
public class ReactionAnalysis {
public static void main (String [] args) throws FileNotFoundException
{
int numberChoice = 0;
//loop everything
while (numberChoice != 5)
{
/// Menu Screen
System.out.println("What would you like to do?");
System.out.println("1: Get the score of a word");
System.out.println("2: Get the average score of words in a file (one word per line)");
System.out.println("3: Find the highest/lowest scoring words in a file");
System.out.println("4: Sort words from a file into positive.txt and negative.txt");
System.out.println("5: Exit the program");
Scanner in = new Scanner(System.in);
System.out.println("Enter a number 1-5");
numberChoice = in.nextInt();
////
if (numberChoice == 1)
{
String methodOne = methodOne();
System.out.println(methodOne);
}
else if (numberChoice == 2)
{
String methodTwo = methodTwo();
System.out.println(methodTwo);
}
else if (numberChoice == 3)
{
String methodThree = methodThree();
System.out.println(methodThree);
}
else if (numberChoice == 4)
{
String methodFour = methodFour();
System.out.println(methodFour);
}
}
}
}