Question

我希望这一年从August开始，然后在以下July结束。除了编写我每年必须写的丑陋IFELSE语句之外，还有一种简单的方法吗？理想情况下，我希望有一年如2009-10，2010-11等。我使用Postgres。

以下是我想操作以获取自定义年份的示例查询。

Select extract(year from created) as Year, type, count(*) 
from table
group by Year, type
order by Year

任何帮助将不胜感激，TIA。

Answer 1

考虑设置日期表。使用此日期表，您可以将各种数据与每个日期相关联，例如会计年度，季度，月份＃，是假日，周末等。

Answer 2

SELECT (CASE WHEN (EXTRACT(month FROM created) > 6) THEN CAST(EXTRACT(year FROM created) AS text) || '-' || CAST(EXTRACT(year FROM created) +1 AS text) ELSE (CAST(EXTRACT(year FROM created) - 1 AS text) || '-' || CAST(EXTRACT(year FROM created) AS text)) END) AS CustomYear
FROM asmt.testscores order by created desc LIMIT 10000

这似乎已经成功了。

Answer 3

select
    extract(year from created + interval '6 months') as "Year",
    type,
    count(*) 
from table
group by 1, 2
order by 1

有自定义年份，而不是日历年

3 个答案: