Question

这是在我使用的聊天室中运行主持人机器人的代码的一部分。代码的这一部分是批准某人的请求，但每当我使用该命令时，我都会收到此未绑定的本地错误... 我已经经历了这么多次，我无法弄清楚为什么我会得到它。

def approveCam(room, identifier):
    if not room.bpass:
        return

    if type(identifier) in [str, unicode, int]:
        user = room._getUser(identifier)
        if not user:
            return "User " + str(identifier) + " was not found..."

    if user.broadcasting:
        return

    room._sendCommand("privmsg", [room._encodeMessage("/allowbroadcast " + room.bpass),
    "#0,en" + "n" + str(user.id) + "-" + user.nick])

问题似乎是“if user.broadcasting：”

代码在此前的机器人版本上工作

def approveCam(room, user):
    if type(user) is str or type(user) is unicode:
        nick = user
        user = room._getUser(user)
    if not user:
        return "User "+nick+" was not found..."

    if not room.bpass:
        return

    room._sendCommand("privmsg", [room._encodeMessage("/allowbroadcast "+room.bpass),
    "#0,en"+"n"+ user.id+"-"+user.nick])

这是我尝试运行命令时在命令提示符下的响应。

Traceback (most recent call last):
 File "C:\Users\Ejah\Downloads\Desktop\Tunebot-Master\tinychat.py", line     1262
in onMessage
  SETTINGS['onMessageExtend'](self, user, msg)
 File "tunebot.py", line 1316, in onMessageExtended
  handleUserCommand(room, user, msg)
 File "tunebot.py", line 1722, in handleUserCommand
  res = botterCommands(room, userCmd, userArgsStr, userArgs, target,
 File "tunebot.py", line 2786, in botterCommands
  res = approveCam(room, user)
 File "tunebot.py", line 4043, in approveCam
  if user.broadcasting:
UnboundLocalError: local variable 'user' referenced before assignment"

Answer 1

更新您的代码，以便在identifier属于无效类型时引发错误，并且一切都将变得清晰：

def approveCam(room, identifier):
    if not room.bpass:
        return

    if type(identifier) in [str, unicode, int]:
        user = room._getUser(identifier)
        if not user:
            return "User " + str(identifier) + " was not found..."
    else:
        raise ValueError('Invalid type for identifier')

    if user.broadcasting:
        return

    room._sendCommand("privmsg", [room._encodeMessage("/allowbroadcast " + room.bpass),
        "#0,en" + "n" + str(user.id) + "-" + user.nick])

Answer 2

user.broadcasting - This is not correct

此时用户不存在，因此解释器不允许这样做。您必须在使用之前初始化局部变量。

使用户成为具有一定价值的全局变量。

Answer 3

可能if type(identifier) in [str, unicode, int]:为False，因此if的正文未执行，user永远不会被初始化。

如果可能，请在第二个user之前初始化if，或重新考虑您的代码。

P.S。不要使用getter和setter！ Python不是Java，如果你真的需要使用它，请改用属性。

UnboundLocalError：赋值前引用的局部变量'user'

3 个答案: