Question

我的表格中有一列具有以下值

|         loan_no                  |

|  SSS Pensioner Loan (C000000001) |
|  SSS SSS Loan (C000000002)       |
|  SSS Salary Loan (C000000007)    |
|  SSS PAGIBIG Loan (C000000003)   |

如何仅选择括号内的值得到这样的结果：

|  loan_no    |

|  C000000001 |
|  C000000002 |
|  C000000007 |
|  C000000003 |

提前谢谢你:) 我正在使用SQL Server 2008 R2

Answer 1

CHARINDEX将帮助您Reference

declare @temp table        
(val nvarchar(77))

insert into @temp values ('SSS Pensioner Loan (C000000001)')
insert into @temp values ('SSS SSS Loan (C000000002)      ')
insert into @temp values ('SSS Salary Loan (C000000007)   ')
insert into @temp values ('SSS PAGIBIG Loan (C000000003)  ')



SELECT 
SUBSTRING(val,CHARINDEX('(', val) + 1,CHARINDEX(')', val) - CHARINDEX('(', val) - 1) as Val
from @temp

Answer 2

试试这个..

declare @table table (loan nvarchar(100))
insert into @table
select 'SSS Pensioner Loan (C000000001)'
union all select 'SSS SSS Loan (C000000002)'   
union all  select 'SSS Salary Loan (C000000007)'   
  union all select 'SSS PAGIBIG Loan (C000000003)'


  select substring (loan,CHARINDEX('(', loan)+1,CHARINDEX(')', loan)-CHARINDEX('(', loan)-1)
  from @table

Answer 3

您可以对mysql使用substring和instr函数（对于sql server，您可以使用charindex代替instr）：

SELECT SUBSTRING(loan_no, INSTR(loan_no, '(')+1,INSTR(loan_no, ')')-INSTR(loan_no, '(')-1) AS loan_no, INSTR(loan_no, ')') AS loan_no

FROM Table

SQL选择括号内的值

3 个答案: