Question

这很好..

  SELECT CM.CMN_CODE,CM.CMN_NAME
      --(SELECT CMPI_PRCINX FROM CMD_MTRL_PRICE_INF WHERE ROWNUM = 1 ORDER BY CMPI_PRCINX DESC) as k
  FROM CMN_MST CM LEFT JOIN CMD_MTRL_INF CMI ON CM.CMN_CODE=CMI.CMN_CDTY_MTRL 
  LEFT JOIN CMD_MTRL_PRICE_INF CMPI ON CMI.CMI_CODE = CMPI.CMI_CODE
  WHERE CM.CTYP_CODE IN (SELECT CTYP_CODE FROM CTYP_MST WHERE CTYP_NAME = 'Common Material');

但这件事给我带来了麻烦。

SELECT CM.CMN_CODE,CM.CMN_NAME,
    (SELECT CMPI_PRCINX FROM CMD_MTRL_PRICE_INF WHERE ROWNUM = 1 ORDER BY CMPI_PRCINX DESC) AS K
FROM CMN_MST CM LEFT JOIN CMD_MTRL_INF CMI ON CM.CMN_CODE=CMI.CMN_CDTY_MTRL 
LEFT JOIN CMD_MTRL_PRICE_INF CMPI ON CMI.CMI_CODE = CMPI.CMI_CODE
WHERE CM.CTYP_CODE IN (SELECT CTYP_CODE FROM CTYP_MST WHERE CTYP_NAME = 'Common Material');

SQL Error: ORA-00907: missing right parenthesis 00907. 00000 - "missing right parenthesis"

也尝试了

  DECLARE 
  PCMPI_PRCINX NUMERIC;
  BEGIN
  SELECT CMPI_PRCINX INTO PCMPI_PRCINX FROM CMD_MTRL_PRICE_INF WHERE ROWNUM = 1 ORDER BY CMPI_PRCINX DESC;
  --SELECT CMPI_PRCINX FROM CMD_MTRL_PRICE_INF WHERE ROWNUM = 1 ORDER BY CMPI_PRCINX DESC;
  SELECT CM.CMN_CODE,CM.CMN_NAME
      --(SELECT CMPI_PRCINX FROM CMD_MTRL_PRICE_INF WHERE ROWNUM = 1 ORDER BY CMPI_PRCINX DESC) AS K,
      PCMPI_PRCINX AS PREVPRICE,    
      CMPI.CMPI_UPDATE_STS
  FROM CMN_MST CM LEFT JOIN CMD_MTRL_INF CMI ON CM.CMN_CODE=CMI.CMN_CDTY_MTRL 
  LEFT JOIN CMD_MTRL_PRICE_INF CMPI ON CMI.CMI_CODE = CMPI.CMI_CODE
  WHERE CM.CTYP_CODE IN (SELECT CTYP_CODE FROM CTYP_MST WHERE CTYP_NAME = 'Common Material');
  END;
  /

Answer 1

我认为你需要重新考虑这部分问题：

  ,(select cmpi_prcinx
      from cmd_mtrl_price_inf
     where rownum = 1
     order by cmpi_prcinx desc) as k

这将从cmpi_prcinx返回第一行，然后应用订单。所以它不会像你期望的那样返回cmpi_prcinx的最大值。

你可以试试这个：

  ,(select max(cmpi_prcinx) from cmd_mtrl_price) as k

Answer 2

尝试

SELECT CM.CMN_CODE,CM.CMN_NAME,
    (SELECT CMPI_PRCINX FROM CMD_MTRL_PRICE_INF WHERE ROWNUM = '1' ORDER BY CMPI_PRCINX DESC) AS K
FROM CMN_MST CM LEFT JOIN CMD_MTRL_INF CMI ON CM.CMN_CODE=CMI.CMN_CDTY_MTRL 
LEFT JOIN CMD_MTRL_PRICE_INF CMPI ON CMI.CMI_CODE = CMPI.CMI_CODE
WHERE CM.CTYP_CODE IN (SELECT CTYP_CODE FROM CTYP_MST WHERE CTYP_NAME = 'Common Material');

其中ROWNUM = 1已由ROWNUM ='1'

更改

Answer 3

试试这个..

SELECT CM.CMN_CODE,CM.CMN_NAME,
    (SELECT TOP 1 CMPI_PRCINX FROM CMD_MTRL_PRICE_INF WHERE ROWNUM = 1 ORDER BY CMPI_PRCINX DESC) AS K
FROM CMN_MST CM LEFT JOIN CMD_MTRL_INF CMI ON CM.CMN_CODE=CMI.CMN_CDTY_MTRL 
LEFT JOIN CMD_MTRL_PRICE_INF CMPI ON CMI.CMI_CODE = CMPI.CMI_CODE
WHERE CM.CTYP_CODE IN (SELECT CTYP_CODE FROM CTYP_MST WHERE CTYP_NAME = 'Common Material');

选择显示错误中选择 - 缺少右括号

3 个答案: