Question

我的表格如下所示

CREATE TABLE IF NOT EXISTS `testtab` (
    `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
    `name` varchar(100) NOT NULL,
    `auto_num` varchar(100) NOT NULL,
    `seal_num` varchar(100) NOT NULL,
    `arr_date` date NOT NULL,
    `unload_date` date NOT NULL,
    PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=11 ;


INSERT INTO `testtab` (`id`, `name`, `auto_num`, `seal_num`, `arr_date`, `unload_date`) VALUES
  (1, 'contain1', 'AT0000004815', 'CN44178', '2014-11-28', '2014-11-28'),
  (2, 'contain1', 'AT0000004815', 'CN44178', '2014-12-28', '2014-12-28'),
  (3, 'contain1', 'AT0000004815', 'CN44178', '2014-12-28', '2014-11-28'),
  (4, 'contain1', 'AT0000004815', 'CN44178', '2014-11-28', '2014-12-28'),
  (5, 'contain2', 'AT0000000227', 'CG11818', '2015-09-12', '2015-08-30'),
  (6, 'contain2', 'AT0000000227', 'CG11818', '2015-08-30', '2015-08-30'),
  (7, 'contain2', 'AT0000000227', 'CG11818', '2015-09-12', '2015-09-14'),
  (8, 'contain2', 'AT0000000227', 'CG11818', '2015-08-30', '2015-09-14'),
  (9, 'contain3', 'AT0000005297', 'FG1005G', '2015-01-25', '2015-01-27'),
  (10, 'contain3', 'AT0000005297', 'FG1005G', '2015-01-25', '2014-12-27');

我需要输出结果，如下所示 Mysql查询结果必须包含arr_date，unload_date中的最大日期值按字段分组：name，auto_num，seal_num

id  name        auto_num        seal_num    arr_date    unload_date 
2   contain1    AT0000004815    CN44178     2014-12-28  2014-12-28
7   contain2    AT0000000227    CG11818     2015-09-12  2015-09-14
9   contain3    AT0000005297    FG1005G     2015-01-25  2015-01-27

我想在这里使用什么查询，请帮助我，

Answer 1

你可以这样做：

SELECT * FROM `testtab` t
WHERE (t.arr_date,t.unload_date) in(select max(arr_date),max(unload_date)
                                    from `testtab` s where s.name = t.name
                                    and s.auto_num = t.auto_num and s.seal_num = t.seal_num)

这将为每个组合（name，auto_num，seal_num）选择max arr_date和unload_date，然后检查行中两列是否相等，选择它。

Answer 2

我猜您正在为arr_date，unload_date和name的每个不同组合寻找最新的auto_num和seal_num。但是你还没有解释你的表格内容，所以我猜错了。

SQL Fiddle

此查询为您提供。它不给出行ID，因为最新的arr_date和最新的unload_date可能来自不同的行。

select name, auto_num, seal_num, 
       MAX(arr_date) arr_date, MAX(unload_date) unload_date
  from testtab
 group by name, auto_num, seal_num

<强> Results ：

|     name |     auto_num | seal_num |          arr_date |       unload_date |
|----------|--------------|----------|-------------------|-------------------|
| contain1 | AT0000004815 |  CN44178 |  December, 28 2014|  December, 28 2014|
| contain2 | AT0000000227 |  CG11818 | September, 12 2015| September, 14 2015|
| contain3 | AT0000005297 |  FG1005G |   January, 25 2015|   January, 27 2015|

MYSQL查询只需要按字段获取更改日期值

2 个答案: