按日期分组仅包含特定日期

Question

我试过看一些类似的例子，例如按日期范围和工作日等分组，但我无法在我的查询中修复它。

根据我的示例数据截图，我只需要返回

Image

和

sum(salesamount)/sum(salescount) for week 1 

每周都包含5天（在此示例中为sum(salesamount)/sum(salescount) for week 2. ）。

我的尝试：

wednesday - sunday

我想要的输出是：

select salesstartdate, date_add(salesstartdate, interval 5 day) as gdate,
    salesamount, salescount, sum(salesamount)/sum(salescount) as ATV
from testing
group by gdate;

获取Week 1 15.34173913 Week 2 15.80365088 的计算是week 1

获取(3507.1+3639.97+5258.77+8417.04+5994.48)/(285+273+344+478+368)的计算与上述相同，但日期现在为6月8日至12日。

Answer 1

您可以使用子查询执行此操作。为了首先对结果集进行正确分组，然后对其执行聚合：

SELECT 
    concat('WEEK', ' ', weekno) as `Week #`,
    MIN(salesstartdate) as startDate,
    MAX(salesstartdate) as endDate,
    sum(salesamount)/sum(salescount) as ATV
FROM
    (
        SELECT 
            salesstartdate,         
            salesamount, 
            salescount,
            WEEKOFYEAR(salesstartdate) as weekno    -- get the week number of the current year
        FROM
            weekno
        WHERE
            WEEKDAY(salesstartdate) BETWEEN 2 AND 6 -- get index of week day
    ) as weeks
GROUP BY
    weekno

我在这里使用了2个MySQL函数：

• WEEKOFYEAR()
• WEEKDAY()

输出：

WEEK 23 | 2016-06-08 | 2016-06-12 | 15.8040
WEEK 24 | 2016-06-16 | 2016-06-19 | 15.9323

并且没有子查询：

SELECT 
    concat('WEEK', ' ', WEEKOFYEAR(salesstartdate)) as `Week #`,
    MIN(salesstartdate) as startDate,
    MAX(salesstartdate) as endDate,
    sum(salesamount)/sum(salescount) as ATV
FROM
    weekno
WHERE
    WEEKDAY(salesstartdate) BETWEEN 2 AND 6 -- get index of week day
GROUP BY
    WEEKOFYEAR(salesstartdate)

Answer 2

你可以这样做

select SUBDATE(salesstartdate, WEEKDAY(salesstartdate)) as week_range
    , sum(salesamount)/sum(salescount)
from testing
where salesstartdate between SUBDATE(salesstartdate, WEEKDAY(salesstartdate)) 
    and  date_add(SUBDATE(salesstartdate, WEEKDAY(salesstartdate)), interval 5 day))
Group by week_range