错误消息

Question

在Linux服务器上，我有一个ajax表单，发布到js脚本，然后发送到php例程发送网站电子邮件联系表单（Styleshout-Puremedia模板）。我知道帖子发生在js和php页面上。我在php页面上遇到一个httpd服务器错误＆＃34; $ Error未定义＆＃34;。但是，如果我将其定义为NULL或＆＃39;＆＃39;它存在，因此没有通过测试＆＃34; if（！$ Error）＆＃34;。如果我使用邮件功能创建一个硬编码的PHP脚本，电子邮件的工作原理，所以php和sendmail都配置正确。有人可以帮助解释为什么这个PHP脚本不起作用，或者如何修复＆＃34; $ Error＆＃34;错误？

PHP代码：

＆＃13;

＆＃13;

<?php

// Replace this with your own email address
$siteOwnersEmail = 'info@mydomain.com';


if($_POST) {
	
   $fname = trim(stripslashes($_POST['contactFname']));
   $lname = trim(stripslashes($_POST['contactLname']));
   $email = trim(stripslashes($_POST['contactEmail']));
   $subject = trim(stripslashes($_POST['contactSubject']));
   $contact_message = trim(stripslashes($_POST['contactMessage']));

   // Check First Name
	if (strlen($fname) < 2) {
		$error['fname'] = "Please enter your first name.";
	}
	// Check Last Name
	if (strlen($lname) < 2) {
		$error['lname'] = "Please enter your last name.";
	}
	// Check Email
	if (!preg_match('/^[a-z0-9&\'\.\-_\+]+@[a-z0-9\-]+\.([a-z0-9\-]+\.)*+[a-z]{2}/is', $email)) {
		$error['email'] = "Please enter a valid email address.";
	}
	// Check Message
	if (strlen($contact_message) < 15) {
		$error['message'] = "Please enter your message. It should have at least 15 characters.";
	}
   // Subject
	if ($subject == '') { $subject = "Contact Form Submission"; }

	// Set Name
	$name = $fname . " " . $lname;

   // Set Message
   $message = "Email from: " . $name . "<br />";
   $message .= "Email address: " . $email . "<br />";
   $message .= "Message: <br />";
   $message .= $contact_message;
   $message .= "<br /> ----- <br /> This email was sent from your site's contact form. <br />";

   // Set From: header
   $from =  $name . " <" . $email . ">";

   // Email Headers
	$headers = "From: " . $from . "\r\n";
	$headers .= "Reply-To: ". $email . "\r\n";
 	$headers .= "MIME-Version: 1.0\r\n";
	$headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n";


   if (!$error) {

      ini_set("sendmail_from", $siteOwnersEmail); // for windows server
      $mail = mail($siteOwnersEmail, $subject, $message, $headers);

		if ($mail) { echo "OK"; }
      else { echo "Something went wrong. Please try again."; }
		
	} # end if - no validation error

	else {

		$response = (isset($error['fname'])) ? $error['fname'] . "<br /> \n" : null;
		$response .= (isset($error['lname'])) ? $error['lname'] . "<br /> \n" : null;
		$response .= (isset($error['email'])) ? $error['email'] . "<br /> \n" : null;
		$response .= (isset($error['message'])) ? $error['message'] . "<br />" : null;
		
		echo $response;

	} # end if - there was a validation error

}

?>

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＆＃13;

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感谢您的帮助!!

-Rob

Answer 1

您始终可以将$ error初始化为

$error = [];

然后通过

检查错误

if(count($errors) === 0){
    //no errors
}

或者，只需使用if(!isset($error)){//no errors}