Question

我有一个基本的联系表单，可以获取人名，电子邮件和评论，然后通过电子邮件发送给他们。所有字段都是必需的，我在发送电子邮件之前检查了我的php文件中的输入。但是现在，如果单击提交后其中一个输入出现错误，则会打开新页面并显示错误消息。我怎样才能在输入下方显示错误消息？

这是我的php文件：

<?php
if(isset($_POST['email'])) {

    $email_to = "email@address.com";
    $email_subject = "Personal Website Contact Form";

    function died($error) {
        // your error code can go here
        echo "We are very sorry, but there were error(s) found with the form you submitted. ";
        echo "These errors appear below.<br /><br />";
        echo $error."<br /><br />";
        echo "Please go back and fix these errors.<br /><br />";
            die();
    }

    // validation expected data exists
    if(!isset($_POST['first_name']) ||
        !isset($_POST['last_name']) ||
        !isset($_POST['email']) ||
        !isset($_POST['comments'])) {
        died('We are sorry, but there appears to be a problem with the form you submitted.');       
    }

        $first_name = $_POST['first_name']; // required
        $last_name = $_POST['last_name']; // required
        $email_from = $_POST['email']; // required
        $comments = $_POST['comments']; // required

        $error_message = "";
        $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';

    if(!preg_match($email_exp,$email_from)) {
        $error_message .= 'The Email Address you entered does not appear to be valid.<br />';
    }

        $string_exp = "/^[A-Za-z .'-]+$/";

    if(!preg_match($string_exp,$first_name)) {
        $error_message .= 'The First Name you entered does not appear to be valid.<br />';
    }

    if(!preg_match($string_exp,$last_name)) {
        $error_message .= 'The Last Name you entered does not appear to be valid.<br />';
    }

    if(strlen($comments) < 2) {
        $error_message .= 'The Comments you entered do not appear to be valid.<br />';
    }

    if(strlen($error_message) > 0) {
        died($error_message);
    }

    $email_message = "Form details below.\n\n";

    function clean_string($string) {
        $bad = array("content-type","bcc:","to:","cc:","href");
        return str_replace($bad,"",$string);
    }

    $email_message .= "First Name: ".clean_string($first_name)."\n";
    $email_message .= "Last Name: ".clean_string($last_name)."\n";
    $email_message .= "Email: ".clean_string($email_from)."\n";
    $email_message .= "Comments: ".clean_string($comments)."\n";
}

// create email headers
$headers = 'From: '.$email_from."\r\n".
'Reply-To: '.$email_from."\r\n" .
'X-Mailer: PHP/' . phpversion();
@mail($email_to, $email_subject, $email_message, $headers); 

header("location:contact.html");

?>

Answer 1

你可以ajax请求这样做。您可以将帖子请求发送到您的php文件，如Ajax Post Request 并在PHP中处理请求。返回请求错误或成功消息

完整示例：Ajax Request with PHP

在php电子邮件表单中显示错误消息

1 个答案: