在JOIN表上应用DISTINT不起作用

时间:2016-02-05 17:17:03

标签: mysql group-by distinct

我的查询是根据炒菜表(3份)总结费用,结果应该是13000但我得到39000。

# Order table

-------------------------------------------
| Id  | order              | Name | Fee   |
-------------------------------------------
|   1 | SELECT STATEMENT   |  ab  | 13000 | 
-------------------------------------------

# Work table
-----------------------------
| Id  | user id  | order id | 
-----------------------------
|  1  |    123   |    1     | 
|  2  |    123   |    1     | 
|  3  |    123   |    1     | 
-----------------------------


# Query 
SELECT o.order_id, SUM(o.fee) AS total_words
FROM users AS u
LEFT JOIN works AS wr ON wr.user_id = u.id
LEFT JOIN orders AS o ON o.order_id = wr.order_id
    WHERE u.id = 123

# Output =>     
Array
(
     [order_id] => 1
     [fee] => 39000
)

我尝试了DISTINCT和分组,但得到了相同的结果。

1 个答案:

答案 0 :(得分:1)

<强> SQL Fiddle Demo

SELECT `user_id`, SUM(orders.`Fee`)
FROM (SELECT DISTINCT `user_id`, `order_id`
      FROM works
     ) as user_work
JOIN orders
   ON user_work.`order_id` = orders.`Id`
WHERE user_work.user_id = 123

<强>输出

| user_id | SUM(orders.`Fee`) |
|---------|-------------------|
|     123 |             13000 |