我是代码igniter
的新手。我正在尝试使用连接多个表来执行delete
查询,但我在查询中遇到错误。
这是我的查询代码。
$this->db->from('order');
$this->db->join('item_order', 'item_order.order_id = order.order_id','left');
$this->db->join('product', 'product.product_number = item_order.item_number','left');
$this->db->join('product_to_image', 'product_to_image.p_id = product.products_id','left');
$this->db->join('product_to_dropbox', 'product_to_dropbox.products_id = product.products_id','left');
$this->db->where('order.user_name', $ebay_user_name);
$this->db->where('order.user_id', $user_id);
$this->db->delete('order');
答案 0 :(得分:0)
使用Codeigniter时,您无法使用DELETE
执行Join
。 see here和here。
您需要编写一个自然的SQL。见链接1:
$sql = "DELETE o FROM order as o
LEFT JOIN item_order ON item_order.order_id = order.order_id
LEFT JOIN product ON product.product_number = item_order.item_number
LEFT JOIN product_to_image ON product_to_image.p_id = product.products_id
LEFT JOIN product_to_dropbox ON product_to_dropbox.products_id = product.products_id
WHERE order.user_name = ? and order.user_id = ?";
$this->db->query($sql, array($ebay_user_name, $user_id));
或尝试用反引号`。但我不确定是否逃避它们:
$sql = "DELETE o FROM `order` as o
LEFT JOIN `item_order` ON item_order.order_id = order.order_id
LEFT JOIN `product` ON product.product_number = item_order.item_number
LEFT JOIN `product_to_image` ON product_to_image.p_id = product.products_id
LEFT JOIN `product_to_dropbox` ON product_to_dropbox.products_id = product.products_id
WHERE order.user_name = ? and order.user_id = ?";
$this->db->query($sql, array($ebay_user_name, $user_id));