Question

每当我尝试在Player类中包含 Hand 对象时，我都会收到以下错误。一旦调用 Player 类的构造函数，它就会显示以下错误消息：

架构x86_64的未定义符号： “ Hand :: Hand（）”，引自：在player-939de2中 Player :: Player（）。 ld：找不到架构x86_64的符号

Player.h

#ifndef h_player
#define h_player
#include <string>
#include "hand.h"
using namespace std;


class Player{

private:
    Hand* hand;
    string name;

public:
    Player();
    void setName(string);
    void setHand(Card);
    string print() const;
    void showHand() const;
};

#endif

Player.cpp

#include <iostream>
#include <string>
#include "player.h"
#include <iomanip>
using namespace std;


Player::Player() {
    name = "";
    hand = new Hand();
    //std::cout<< "here";
}

void Player::setName(string name) {
    this->name = name;
}

string Player::print() const {
    return this->name;
}

void Player::setHand(Card add) {
    hand->addCard(add);
}

void Player::showHand() const {

    for(int i = 0; i < 7; i++) {
        Card myCard = hand->showCard();
        std::cout << "|" << std::setfill(' ') << std::setw(18) << std::right << myCard.print() << std::setfill(' ') << std::setw(18) << std::right << "|" << std::endl;
    }
}

Hand.h

#ifndef h_hand
#define h_hand
#include <string>
#include "card.h"

using namespace std;

const int number_of_cards = 7;

class Hand {

private:
    Card *cards;
    int no_of_books;
    int cards_remaining;
public:
    Hand();
    void addCard(Card);
    bool checkHand();
    Card showCard() const;
    void withdraw();

};

#endif

Hand.cpp

#include <iostream>
#include <string>
#include "hand.h"
using namespace std;

Hand::Hand() {
    cards = new Card[7];
    cards_remaining = 7;
    no_of_books = 0;
}

void Hand::addCard(Card add) {

    if(cards_remaining > 0) {
        cards[cards_remaining] = add;
        cards_remaining--;
    }
}

Card Hand::showCard() const {
    return cards[cards_remaining++];
}

类中的对象 - 未定义的符号错误

0 个答案: