Question

我正在努力寻找已弃用的DefaultHttpClient和已联系的类HttpPost等的替代品。

第一次尝试时，我尝试使用volley库，但似乎没有任何效果，所以经过一些研究后我现在正在尝试使用Retrofit 1.9。

在我的应用中，我连接到一个自己的宁静客户端。这是旧代码（示例POST），它运行得非常好：

    private static DefaultHttpClient httpClient = new DefaultHttpClient();

    public static String executePOST(Map<String, String> postParams, int connTO, int sockTO, String uri){

        String res, message;
        HttpParams httpParams = new BasicHttpParams();
        HttpConnectionParams.setConnectionTimeout(httpParams, connTO);
        HttpConnectionParams.setSoTimeout(httpParams, sockTO);
        HttpConnectionParams.setTcpNoDelay(httpParams, true);

        httpClient.setParams(httpParams);

        HttpPost httppost = new HttpPost(uri);
        JSONObject json = new JSONObject();

        try {
            Iterator<Entry<String, String>> iterator = postParams.entrySet().iterator();

            while(iterator.hasNext()){
                Map.Entry<String, String> pair = (Map.Entry<String, String>)iterator.next();
                json.put(pair.getKey(), pair.getValue());
            }

            message = json.toString();

            httppost.setEntity(new StringEntity(message, "UTF8"));
            httppost.setHeader("Accept", "application/json");
            httppost.setHeader("Content-type", "application/json");

            HttpResponse response = httpClient.execute(httppost);
            HttpEntity entity = response.getEntity();           
            res = EntityUtils.toString(entity).trim();

        } catch (ClientProtocolException e) {
            res = "Client Protocol Exception";
        } catch (IOException e) {
            res = e.getLocalizedMessage();
        } catch (JSONException e){
            res = e.getLocalizedMessage();
        }

        return res;
    }

我从我的活动

发送这样的请求

Map<String, String> arguments = new HashMap<String, String>();
        arguments.put("email", username);
new HttpClient(arguments, new LoginActivityCommunicationListener(this, LoginOperation.EMAIL_CHECK), URI_ROOT + "/kunde", 0).execute();

参数中的侦听器处理响应回调，0表示POST。

这会产生JSON响应，包含字段id和person

所以我尝试像这样实现上面的Retrofit变种

MyApi.java

public interface MyDosAPI {

    @FormUrlEncoded
    @POST("/kunde")
    public void checkEmail(@Field("email") String email, Callback<EmailCheck> response);
}

EmailCheck.java

public class EmailCheck {

    @SerializedName("id")
    private String id;

    @SerializedName("person")
    private String person;

    public void setId(String id){
        this.id = id;
    }

    public void setPerson(String person){
        this.person = person;
    }

    public String getId(){
        return id;
    }

    public String getPerson(){
        return person;
    }
}

并在活动中

RestAdapter adapter = new RestAdapter.Builder()
                .setEndpoint(URI_ROOT)
                .build();

        MyDosAPI api = adapter.create(MyDosAPI.class);

        api.checkEmail(username, new Callback<EmailCheck>() {
            @Override
            public void success(EmailCheck emailChecks, Response response) {
                Log.i("MyCount", "success");
            }

            @Override
            public void failure(RetrofitError error) {
                Log.i("MyCount", error.getMessage());
            }
        });

结果

com.google.gson.JsonSyntaxException: java.lang.IllegalStateException: Expected BEGIN_OBJECT but was STRING at line 1 column 1 path $

显然，我缺少一些必不可少的东西。是否 - 除了Retrofit或Volley之外 - 我可以像以前一样定义请求的另一个解决方案？

Answer 1

更改为：

public interface MyDosAPI {
  @POST("/kunde")
  public void checkEmail(@Body String email, Callback<EmailCheck> response);
}

Android：从DefaultHttpClient到Retrofit

1 个答案: