matplotlib：格式轴不带偏移量

Question

我想将我的刻度格式化为一定数量的有效数字，并删除自动偏移量。对于后者，我使用的是https://stackoverflow.com/a/6654046/1021819，对于前者，我会使用https://stackoverflow.com/a/25750438/1021819，即

var test1,test2,test3;

Object.prototype.getInfo = function(){
    return this.firstName + " - " + this.lastName;
}

function test1(){
    this.firstName = "ham";
}

test2.prototype = test1;
function test2(){
    this.lastName = "bam";
}

test3.prototype = test2;
function test3(){
    return this.getInfo();
}

test1(); // at this level firstName property is available
test2(); // at this level firstName,lastName  properties are available
test3(); // returns 'ham - bam' because the main prototype Object has the method getInfo and we have firstName,lastName from the previous prototypes.

和

y_formatter = matplotlib.ticker.ScalarFormatter(useOffset=False)
ax.yaxis.set_major_formatter(y_formatter)

如何组合FormatStrFormatter和useOffset语法？

Answer 1

FormatStrFormatter没有使用偏移量，因此通过使用第二种格式，您将自动获得偏移量。

比较此示例中的两个子图

import matplotlib.pyplot as plt
import matplotlib.ticker as mtick
import numpy as np  

fig,(ax1,ax2)=plt.subplots(2)

ax1.plot(np.arange(10000,10010,1))

ax2.plot(np.arange(10000,10010,1))
ax2.yaxis.set_major_formatter(mtick.FormatStrFormatter('%.4e'))

plt.show()