Question

我有表catalog_view。我包含指定类别的联系人。联系人可以有几个类别。我想选择属于所有用户类别选择的联系人

e.g contact "Jone" belongs to categories [1,2,3,4,5,6] and contact "Jay" belongs to categories [1,3]. If user select categories [2,3], only "Jone" should be returned, if [1]|[3]|[1,3] selected, both should be returned, if [7]|[1,7] selected, none should be returned.

我应该如何构建查询和/或更改表来实现它？

查询按单个类别选择联系人

SELECT * FROM catalog_view WHERE (category_id = ?)

此查询选择记录，如果分配的类别与其中任何一个匹配，并返回联系人行数达到参数数量，也不会强制选择所有参数。

SELECT * FROM catalog_view WHERE (category_id = ? OR category_id = ? OR category_id =?)

此查询始终返回空表，因为catalog_view的当前模板中的行只有一个category_id

SELECT * FROM catalog_view WHERE (category_id = ? AND category_id = ? AND category_id =?)

联系人

CREATE TABLE IF NOT EXISTS contacts_table(_id integer primary key, title text default '',title_lower text default '',title_short text default '',photo blob, number text default '', note text default '', note_lower text default '', email text, partner int default '0', contact_id int default '0', current_user text default '', categories text default '', saved integer default '0' );

类别

CREATE TABLE IF NOT EXISTS categories_table(_id integer primary key, category_id integer, parent_id integer, name text, section_name text, current_user text, sub_name text default '' );

与类别的联系

CREATE TABLE IF NOT EXISTS contacts_categories_table(_id integer primary key, contact_id integer, category_id integer, current_user text );

目录查看联系人

CREATE VIEW IF NOT EXISTS catalog_view AS  SELECT contacts_table._id AS _id, contacts_table.contact_id, contacts_table.title_lower, contacts_table.note_lower, contacts_table.current_user, contacts_table.saved, contacts_table.partner, contacts_table.title, contacts_table.email, contacts_table.title_short, contacts_table.number, contacts_table.note, contacts_table.categories, categories_table.section_name, contacts_table.contact_id, categories_table.parent_id, categories_table.category_id  FROM contacts_categories_table INNER JOIN contacts_table ON(contacts_categories_table.contact_id = contacts_table.contact_id AND contacts_categories_table.current_user = contacts_table.current_user)  LEFT OUTER JOIN categories_table ON(contacts_categories_table.category_id = categories_table.category_id AND contacts_categories_table.current_user = categories_table.current_user)

Answer 1

您可以尝试以下内容：

SELECT distinct name from catalog_view s
where NUMBER_OF_CONTACT_SELECTION =
      (SELECT count(*) from catalog_view t
      where t.name = s.name and
      category_id in(YOUR CONTACT SELECTION HERE IN FORMAT OF 1,3,4...))

因此1,3您的查询应该是：

SELECT distinct name from catalog_view s
where 2 =
      (SELECT count(*) from catalog_view t
      where t.name = s.name and
      category_id in(1,3))

对于1,2,4,7它应该是 - ＆gt; 4 =（..... IN（1,2,4,7））

如何在所有参数中选择记录匹配？

1 个答案: