Question

我试图弄清楚看起来应该很简单的事情。我试图从名称中删除中间的首字母，但我不知道如何在不为字母表的每个字母创建replace（）的情况下执行此操作。这就是我正在寻找的：

（开始时）

＆＃34; John D Smith＆＃34;

＆＃34; Robert B Johnson＆＃34;

（结束）

＆＃34; John Smith＆＃34;

＆＃34;罗伯特约翰逊＆＃34;

在Python中完成上述操作的最简单方法是什么？中间的首字母是随机的，但总是被白色空间包围。

Answer 1

根据您的帖子提供此帮助

>>> import re
>>> re.sub(' [A-Z]* ', ' ', "John D Smith")
'John Smith'
>>> re.sub(' [A-Z]* ', ' ', "Robert B Johnson")
'Robert Johnson'

Answer 2

内置字符串操作非常简单。

name = "Name N Name".split() # Splits string at whitespace into list
del name[1] # Deletes 2nd item (middle initial)
removed_middle_initial = " ".join(name) # "Name Name"

这假设名字和姓氏不包含任何空格字符。如果需要更高级的要求，那么显然需要处理这些条件。

Answer 3

(?=)展望未来。 [A-Z]首字母为1个字母。

import re
re.sub(' [A-Z](?= )', '', "John D Smith")

Answer 4

您可以使用sub方法将中间的首字母替换为空格。

#import <Foundation/Foundation.h>

#import "gmail.h"

static NSString *const kKeychainItemName = @"Gmail API";
static NSString *const kClientID = @"this is my key";

@implementation gmail

@synthesize service = _service;
@synthesize output = _output;

// When the view loads, create necessary subviews, and initialize the Gmail API service.
- (void)viewDidLoad {
  [super viewDidLoad];

  // Create a UITextView to display output.
  self.output = [[UITextView alloc] initWithFrame:self.view.bounds];
  self.output.editable = false;
  self.output.contentInset = UIEdgeInsetsMake(20.0, 0.0, 20.0, 0.0);
  self.output.autoresizingMask = UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleWidth;
  [self.view addSubview:self.output];

  // Initialize the Gmail API service & load existing credentials from the keychain if available.
  self.service = [[GTLServiceGmail alloc] init];
  self.service.authorizer =
  [GTMOAuth2ViewControllerTouch authForGoogleFromKeychainForName:kKeychainItemName
                                                        clientID:kClientID
                                                    clientSecret:nil];
}

// When the view appears, ensure that the Gmail API service is authorized, and perform API calls.
- (void)viewDidAppear:(BOOL)animated {
  if (!self.service.authorizer.canAuthorize) {
    // Not yet authorized, request authorization by pushing the login UI onto the UI stack.
    [self presentViewController:[self createAuthController] animated:YES completion:nil];

  } else {
    [self fetchLabels];
  }
}

// Construct a query and get a list of labels from the user's gmail. Display the
// label name in the UITextView
- (void)fetchLabels {
  self.output.text = @"Getting labels...";
  GTLQueryGmail *query = [GTLQueryGmail queryForUsersLabelsList];
  [self.service executeQuery:query
                    delegate:self
           didFinishSelector:@selector(displayResultWithTicket:finishedWithObject:error:)];
}

- (void)displayResultWithTicket:(GTLServiceTicket *)ticket
             finishedWithObject:(GTLGmailListLabelsResponse *)labelsResponse
                          error:(NSError *)error {
  if (error == nil) {
    NSMutableString *labelString = [[NSMutableString alloc] init];
    if (labelsResponse.labels.count > 0) {
      [labelString appendString:@"Labels:\n"];
      for (GTLGmailLabel *label in labelsResponse.labels) {
        [labelString appendFormat:@"%@\n", label.name];
      }
    } else {
      [labelString appendString:@"No labels found."];
    }
    self.output.text = labelString;
  } else {
    [self showAlert:@"Error" message:error.localizedDescription];
  }
}


// Creates the auth controller for authorizing access to Gmail API.
- (GTMOAuth2ViewControllerTouch *)createAuthController {
  GTMOAuth2ViewControllerTouch *authController;
  NSArray *scopes = [NSArray arrayWithObjects:kGTLAuthScopeGmailReadonly, nil];
  authController = [[GTMOAuth2ViewControllerTouch alloc]
                    initWithScope:[scopes componentsJoinedByString:@" "]
                    clientID:kClientID
                    clientSecret:nil
                    keychainItemName:kKeychainItemName
                    delegate:self
                    finishedSelector:@selector(viewController:finishedWithAuth:error:)];
  return authController;
}

// Handle completion of the authorization process, and update the Gmail API
// with the new credentials.
- (void)viewController:(GTMOAuth2ViewControllerTouch *)viewController
      finishedWithAuth:(GTMOAuth2Authentication *)authResult
                 error:(NSError *)error {
  if (error != nil) {
    [self showAlert:@"Authentication Error" message:error.localizedDescription];
    self.service.authorizer = nil;
  }
  else {
    self.service.authorizer = authResult;
    [self dismissViewControllerAnimated:YES completion:nil];
  }
}

// Helper for showing an alert
- (void)showAlert:(NSString *)title message:(NSString *)message {
  UIAlertView *alert;
  alert = [[UIAlertView alloc] initWithTitle:title
                                     message:message
                                    delegate:nil
                           cancelButtonTitle:@"OK"
                           otherButtonTitles:nil];
  [alert show];
}

@end

这是使用>>> re.sub("\s[A-Za-z]\s", " ", "John D Smith") John Smith字母字符类来查找由空格包围的第一个单个字母。然后用一个空格替换整个3个字符的字符串（空格，字母，空格）。

如何从python中的名称中删除中间的首字母？

5 个答案: