Question

我无法理解，我可以用Json变压器吗？

import play.api.libs.json._

val r = ( __ \ "opt").readNullable[String]
val w = ( __ \ "someOpt").writeNullable[String]

val o1 = Json.obj("noopt" -> "some opt value")
val o2 = Json.obj("opt" -> "some opt value")

r.reads(o1).map(w.writes)
r.reads(o2).map(w.writes)

...

scala> res6: play.api.libs.json.JsResult[play.api.libs.json.JsObject] = JsSuccess({},)

scala> res7: play.api.libs.json.JsResult[play.api.libs.json.JsObject] = JsSuccess({"someOpt":"some opt value"},/opt)

Answer 1

源代码分析导致决定

val t = Reads.nullable[String]( __ \ "opt").map{
  case Some(o) => JsPath.createObj( (__ \ "someOpt") -> JsString(o))
  case _ => Json.obj()
}

或更熟悉（来自Json组合者）

val t = ( __ \ "opt").readNullable[String].map{
  case Some(o) => Json.obj("someOpt" -> o)
  case _ => Json.obj()
}

结果：

val o1 = Json.obj("noopt" -> "some opt value")
val o2 = Json.obj("opt" -> "some opt value")

o1.transform(t)
o2.transform(t)

scala> res23: play.api.libs.json.JsResult[play.api.libs.json.JsObject] = JsSuccess({},)

scala> res24: play.api.libs.json.JsResult[play.api.libs.json.JsObject] = JsSuccess({"someOpt":"some opt value"},/opt)

在Play框架2

1 个答案: