C ++：expression必须是可修改的左值

Question

char message[512];
string info;
...
// read from txt file and save to "info"
...
message = info.c_str();

错误是由最后一行的“消息”引起的。我不熟悉C或C ++，有人能告诉我出了什么问题吗？

Answer 1

const char *message; // needs to be a pointer, not an actual array
string info;
...
// read from txt file and save to "info"
...
message = info.c_str();

Answer 2

你可以这样做：

strncpy(message, info.c_str(), sizeof(message));
message[sizeof(message) - 1] = '\0';