Question

我刚刚开始学习python编程。我试图制作一款类似于口袋妖怪的游戏，我试图将OOP应用到agame中。

我开始制作一个Pokemon类，并添加类定义的属性，如名称，HP，etype，攻击。＆＃34;攻击＆＃34;是一个列表字典。

我现在的问题是我正在尝试开发一个简单的战斗引擎，我可以在其中切换小宠物。出于这个原因，我做了一个函数/方法名称fight（）。

在里面我有一个名为current_pokemon.name的变量，所以每当我关掉口袋妖怪时，我都可以使用新的口袋妖怪的名字，攻击等。

我使用raw_input返回一个替换current_pokemon的字符串，该字符串具有.key属性以在pikachu实例上调用。相反，我得到了＆＃39; str＆＃39;对象没有属性。为什么这不起作用？当我明确写了pikachu.attribute时，它在函数fight（）之外工作。

class Pokemon(object):
    def __init__(self, name, HP, etype, attacks):
        self.name = name
        self.HP = HP
        self.etype = etype
        self.attacks = attacks #2 attacks with name, dmg, type and power points

geodude = Pokemon("Geodude", 100, "Ground", 
                  attacks = 
                  {"Tackle":["Tackle",30,"Normal","35"], 
                   "Rollout":["Rollout",50,"Rock","20"]
                  })
                    #attacks = {attack:[attack_name, dmg, type, PP]}

pikachu = Pokemon("Pikachu", 100, "Lightning", 
                  attacks = 
                  {"Thunder Shock":["Thunder Shock",40,"Electric"],
                   "Quick Attack":["Quick Attack",40,"Normal"]
                  })

#selects pikachu's attack
print "Pokemon's name is", (pikachu.name)
print "Pikachu's %s attack damages %d" % ((pikachu.attacks["Thunder Shock"][0]),(pikachu.attacks["Thunder Shock"][1]))

pikachu.HP = pikachu.HP - geodude.attacks["Rollout"][1]
print "Pikachu's HP is", (pikachu.HP)
pikachu.HP = pikachu.HP - geodude.attacks["Tackle"][1]
print "Pikachu's HP is", (pikachu.HP)

#Pokemon Battle test with stored variable
#Value selector - replace all var attributes using an easy function
#Use Solution 2

def fight():
    current_pokemon = raw_input("pikachu or geodude? > ")
    print current_pokemon.name
    print current_pokemon.attacks


fight()

输出：

Pokemon's name is Pikachu
Pikachu's Thunder Shock attack damages 40
Pikachu's HP is 50
Pikachu's HP is 20
pikachu or geodude? > pikachu
Traceback (most recent call last):
  File "poke_game_stack.py", line 40, in <module>
    fight()
  File "poke_game_stack.py", line 36, in fight
    print current_pokemon.name
AttributeError: 'str' object has no attribute 'name'

请帮助我解决这个简单的问题！谢谢！

Answer 1

raw_input()总是返回一个字符串;它不会返回您使用相同名称存储的对象。

将小宠物存储在字典中（将字符串映射到对象），然后使用raw_input()中的字符串映射到其中一个对象：

pokemons = {
    'geodude': Pokemon("Geodude", 100, "Ground", 
                  attacks = 
                  {"Tackle":["Tackle",30,"Normal","35"], 
                   "Rollout":["Rollout",50,"Rock","20"]
                  }),

    'pikachu': Pokemon("Pikachu", 100, "Lightning", 
                  attacks = 
                  {"Thunder Shock":["Thunder Shock",40,"Electric"],
                   "Quick Attack":["Quick Attack",40,"Normal"]
                  }),
}

def fight():
    current_pokemon_name = raw_input("pikachu or geodude? > ")
    current_pokemon = pokemons[current_pokemon_name]
    print current_pokemon.name
    print current_pokemon.attacks

Answer 2

current_pokemon = raw_input("pikachu or geodude? > ")
print current_pokemon.name
print current_pokemon.attacks

raw_input()方法返回str，字符串没有name或attacks等属性。

该函数从输入中读取一行，将其转换为字符串 （剥离尾随换行符），然后返回。读取EOF时提出了EOFError。

Python＆＃39; str＆＃39;对象没有属性＆＃39; name＆＃39;使用函数变量调用类实例

2 个答案: