Question

这是整个计划。我不确定为什么，但错误说明了这一点，但我使用一个单独的.py程序来测试这个类中的所有函数，我遇到了这个错误，我似乎无法找到解决方案。

File "C:\Python\PythonLab\PythonLab.py\classes.py", line 73, in printEmployeeNames Supervisor.printName(worker) File "C:\Python\PythonLab\PythonLab.py\classes.py", line 56, in printName print(str(self.name) + "'" + str(self.department)) AttributeError: 'str' object has no attribute 'name'

class Employee:

    def __init__(self, fullname, datestart, monthstart, yearstart):
        self.fullname = fullname
        self.datestart = datestart
        self.monthstart = monthstart
        self.yearstart = yearstart

    def getService(self):
        from datetime import date
        current_date = date.today()
        date1 = date(self.yearstart, self.monthstart, 1)
        date_now = date(current_date.year, current_date.month, 1)
        serviceTime = date_now - date1
        day_format = serviceTime.days

        years = int((day_format/365))
        months = int(((day_format % 365)/30))

        if day_format < 0:
            return('Still In Service')
        if day_format == 1:
            return("Last Service Time was Yesterday")
        if day_format < 365:
            return("Last Service Time was " + str(months) + " months ago.")
        if day_format > 365:
            return('Last Service Time was ' + str(years) + "-" + str(months) + " ago.")

    def printName(self):
        print(self.fullname)

    def setName(self, name):
        self.fullname = name


class Supervisor(Employee):

    def __init__(self, name, datestart, department):
        Employee.__init__(self, name, int(datestart[0:2]), int(datestart[2:4]), int(datestart[5:8]))
        self.employees = {}
        self.contact_info = {}
        self.department = department
        self.name = Employee.__name__



    def getName(self):
        return self.fullname

    def printName(self):
        print(str(self.name) + "'" + str(self.department))

    def setName(self, name, department):
        self.name = name
        self.department = department

    def addEmployee(self, Employee):
        self.employees[str(Supervisor.getName(self))] = Employee

    def isManager(self):
        if self.employees:
            return True
        else:
            return False

    def printEmployeeNames(self):
        for worker in self.employees:
            Supervisor.printName(worker)

    def removeEmployee(self, employeename):
        for worker in self.employees:
            if employeename in self.employees:
                del self.employees[employeename]

    def getContactInfo(self):
        return self.employees

    def setContactInfo(self, phone, fax, email):
        self.contact_info["phone"] = phone
        self.contact_info["fax"] = fax
        self.contact_info["email"] = email


    def getPhone(self):
        return self.contact_info["phone"]

    def getFax(self):
        return self.contact_info["fax"]

    def getEmail(self):
        return self.contact_info["email"]

Answer 1

dict是for worker in self.employees: Supervisor.printName(worker)。迭代它意味着迭代它的键。因此，在此代码中

worker

for worker in self.employees: Supervisor.printName(self.employees[worker])是一个字符串。将其更改为：

for name, worker in self.employees.items():  # iterates key-value pairs
    Supervisor.printName(worker)

或者更重要的是：

public function store(Request $request, $post_id){

    $like = Like::create([ 'user_id' => Auth::user()->id, 'post_id' => $post_id]);

    $post = Post::whereId($post_id)->first();

    if( $post->user_id !== Auth::user()->id ) {
        //SEND Notification code here
    }

}

AttributeError：＆＃39; str＆＃39;对象没有属性＆＃39; name＆＃39;但是我在一个类中调用一个函数（？）

1 个答案: