Question

我知道其他人也问了类似的问题，但我还没有看到明确的答案，而且我仍然被困住了。我正在尝试编写一个Swift函数，它接受硬件生成的键盘扫描代码，例如来自NSEvent，并返回密钥的alpha-caps-locked名称，用于特定的键排列（Dvorak，Qwerty等）。）目前在操作系统中有效（可能与生成代码时生效的安排不同）。

我的理解是，这样做的唯一方法是调用一些非常古老的Carbon功能，避开Swift的极端类型安全性，这是我感觉不舒服的事情。这是The Show So Far：

import  Cocoa
import  Carbon

func keyName (scanCode: UInt16) -> String?
  { let maxNameLength = 4,      modifierKeys: UInt32 = 0x00000004   //  Caps Lock (Carbon Era)

    let deadKeys      = UnsafeMutablePointer<UInt32>(bitPattern: 0x00000000),
        nameBuffer    = UnsafeMutablePointer<UniChar>.alloc(maxNameLength),
        nameLength    = UnsafeMutablePointer<Int>.alloc(1),
        keyboardType  = UInt32(LMGetKbdType())

    let source        = TISGetInputSourceProperty ( TISCopyCurrentKeyboardLayoutInputSource()
                                                        .takeRetainedValue(),
                                                    kTISPropertyUnicodeKeyLayoutData )

    let dataRef       = unsafeBitCast(source, CFDataRef.self)
    let dataBuffer    = CFDataGetBytePtr(dataRef)

    let keyboardLayout  = unsafeBitCast(dataBuffer, UnsafePointer <UCKeyboardLayout>.self)

    let osStatus  = UCKeyTranslate  (keyboardLayout, scanCode, UInt16(kUCKeyActionDown),
                        modifierKeys, keyboardType, UInt32(kUCKeyTranslateNoDeadKeysMask),
                        deadKeys, maxNameLength, nameLength, nameBuffer)
    switch  osStatus
      { case  0:    return  NSString (characters: nameBuffer, length: nameLength[0]) as String
        default:    NSLog (“Code: 0x%04X  Status: %+i", scanCode, osStatus);    return  nil   }
  }

它没有崩溃，在这一点上我几乎认为游戏成就本身，但它也不起作用。 UCKeyTranslate总是返回-50的状态，我理解这意味着有一个参数错误。我怀疑“keyboardLayout”，因为它是最复杂的设置。谁能看到参数问题？或者是否有更新的框架来处理这类事情？

Answer 1

正如您已经发现的那样，您必须传递UInt32的地址变量为deadKeyState参数。分配内存是一个解决这个问题的方法，但你不能忘记释放内存最终，否则程序会泄漏内存。

另一种可能的解决方案是将变量的地址作为与&：

的inout-argument

var deadKeys : UInt32 = 0
// ...
let osStatus = UCKeyTranslate(..., &deadKeys, ...)

这有点短，更简单，你不需要释放记忆。这同样适用于nameBuffer和nameLength。

使用unsafeBitCast()类型可以避免Unmanaged，比较Swift: CFArray : get values as UTF Strings是否存在类似问题更详细的解释。

此外，您还可以利用两者之间的免费桥接 CFData和NSData。

然后你的功能看起来像这样（ Swift 2 ）：

import Carbon

func keyName(scanCode: UInt16) -> String?
{
    let maxNameLength = 4
    var nameBuffer = [UniChar](count : maxNameLength, repeatedValue: 0)
    var nameLength = 0

    let modifierKeys = UInt32(alphaLock >> 8) & 0xFF // Caps Lock
    var deadKeys : UInt32 = 0
    let keyboardType = UInt32(LMGetKbdType())

    let source = TISCopyCurrentKeyboardLayoutInputSource().takeRetainedValue()
    let ptr = TISGetInputSourceProperty(source, kTISPropertyUnicodeKeyLayoutData)
    let layoutData = Unmanaged<CFData>.fromOpaque(COpaquePointer(ptr)).takeUnretainedValue() as NSData
    let keyboardLayout = UnsafePointer<UCKeyboardLayout>(layoutData.bytes)

    let osStatus = UCKeyTranslate(keyboardLayout, scanCode, UInt16(kUCKeyActionDown),
        modifierKeys, keyboardType, UInt32(kUCKeyTranslateNoDeadKeysMask),
        &deadKeys, maxNameLength, &nameLength, &nameBuffer)
    guard osStatus == noErr else {
        NSLog("Code: 0x%04X  Status: %+i", scanCode, osStatus);
        return nil
    }

    return  String(utf16CodeUnits: nameBuffer, count: nameLength)
}

Swift 3的更新：

import Carbon

func keyName(scanCode: UInt16) -> String? {
    let maxNameLength = 4
    var nameBuffer = [UniChar](repeating: 0, count : maxNameLength)
    var nameLength = 0

    let modifierKeys = UInt32(alphaLock >> 8) & 0xFF // Caps Lock
    var deadKeys: UInt32 = 0
    let keyboardType = UInt32(LMGetKbdType())

    let source = TISCopyCurrentKeyboardLayoutInputSource().takeRetainedValue()
    guard let ptr = TISGetInputSourceProperty(source, kTISPropertyUnicodeKeyLayoutData) else {
        NSLog("Could not get keyboard layout data")
        return nil
    }
    let layoutData = Unmanaged<CFData>.fromOpaque(ptr).takeUnretainedValue() as Data
    let osStatus = layoutData.withUnsafeBytes {
        UCKeyTranslate($0, scanCode, UInt16(kUCKeyActionDown),
                       modifierKeys, keyboardType, UInt32(kUCKeyTranslateNoDeadKeysMask),
                       &deadKeys, maxNameLength, &nameLength, &nameBuffer)
    }
    guard osStatus == noErr else {
        NSLog("Code: 0x%04X  Status: %+i", scanCode, osStatus);
        return nil
    }

    return  String(utf16CodeUnits: nameBuffer, count: nameLength)
}

Answer 2

好的，我相信我发现了问题。虽然回答我自己的问题很奇怪，但我知道在这样的情况下这是正确的做法。

违规参数似乎已经死了。在我关注的模型代码中，这被定义为一个位模式。虽然据说是指向可变的东西的指针，但我不确定它是不是真的那样，因为当我决定重新定义它以匹配UCKeyTranslate的其他两个call-by-reference参数时，一切都开始完美。解决方案是执行显式.alloc，然后显式调零引用值。这是我的功能更新：

func    keyName       ( scanCode: UInt16  )     ->  String?
  { let maxNameLength = 4,      modifierKeys: UInt32  = 0x00000004,     //  Caps Lock (Carbon Era Mask)
        nameBuffer    = UnsafeMutablePointer <UniChar>  .alloc (maxNameLength),
        nameLength    = UnsafeMutablePointer <Int>      .alloc (1),
        deadKeys      = UnsafeMutablePointer <UInt32>   .alloc (1);     deadKeys[0] = 0x00000000

    let source        = TISGetInputSourceProperty ( TISCopyCurrentKeyboardLayoutInputSource()
                                                        .takeRetainedValue(),
                                                    kTISPropertyUnicodeKeyLayoutData  ),

    keyboardLayout    = unsafeBitCast ( CFDataGetBytePtr (unsafeBitCast (source, CFDataRef.self)),
                                        UnsafePointer <UCKeyboardLayout>.self),
    keyboardType      = UInt32 (LMGetKbdType())

    let osStatus      = UCKeyTranslate (keyboardLayout, scanCode, UInt16 (kUCKeyActionDown),
                            modifierKeys, keyboardType, UInt32 (kUCKeyTranslateNoDeadKeysMask),
                            deadKeys, maxNameLength, nameLength, nameBuffer)
    switch  osStatus
      { case  0:    return  String.init (utf16CodeUnits: nameBuffer, count: nameLength[0])
        default:    NSLog ("Code: 0x%04X  Status: %+i", scanCode, osStatus);    return  nil   }
  }

还有一些其他的变化，非常漂亮：我消除了几个中间常量，导致了keyboardLayout的定义。（“BitCasts”只是为了满足Swiftian类型的安全性：它们并没有真正做我能看到的任何其他事情。）但真正的问题是deadKeys的原始定义。我希望这对某些人有用，至少在有非碳替代方案之前。（这会发生吗？）

在Swift

2 个答案: