Question

我正在编写一个记录用户鼠标移动和点击的程序，并使用Robot类播放它们。

我遇到了这个错误：

Exception in thread "AWT-EventQueue-0" java.lang.IllegalThreadStateException: Cannot call method from the event dispatcher thread

我已经阅读了有关EDT的所有信息，人们一直在提及，必须在另一个线程中运行它才能退出EDT。

我的问题是：即使我使用了一个新主题，为什么我的代码也不起作用？

以下是代码：

void doAction(Robot robert) {
    int x = ((MouseEvent) event).getXOnScreen();
    int y = ((MouseEvent) event).getYOnScreen();
    Thread safe = new Thread(new Runnable() {
        @Override
        public void run() {
            System.out.println(SwingUtilities.isEventDispatchThread());
            MouseEvent m = (MouseEvent) this.event; // event is the recording of the click
            robert.mouseMove(x, y); // error traces back to here
            leftClick(robert);
        }
    });
    safe.run();
}

System.out.println(SwingUtilities.isEventDispatchThread());打印真实

整个班级代码在这里：

class RoboMouseClick extends RoboAction {

    AWTEvent event;

    public RoboMouseClick(String mouse, int MOUSE_MOVE, AWTEvent event,
            long timeStamp) {
        super(mouse, MOUSE_MOVE, timeStamp);
        this.event = event;
    }

    private void leftClick(Robot robot)
    {
        robot.mousePress(InputEvent.BUTTON1_MASK);
        robot.delay(200);
        robot.mouseRelease(InputEvent.BUTTON1_MASK);
        robot.delay(200);
    }

    void doAction(Robot robert) {
        int x = ((MouseEvent) event).getXOnScreen();
        int y = ((MouseEvent) event).getYOnScreen();
        Thread safe = new Thread(() -> {
            System.out.println(SwingUtilities.isEventDispatchThread());
            MouseEvent m = (MouseEvent) event;
            robert.mouseMove(x, y);
            leftClick(robert);
        });
        safe.run();
    }
}

Answer 1

您必须调用方法：

const PureComponent = ({url}) => (
  <div>
    <a href={url}>{children}</a> // <--- This doesn't work
  </div>
);

<PureComponent url="http://www/google.ca">Google Canada</PureComponent>

// I want to render this:
<a href="http://www.google.ca">Google Canada</a>

而不是

Thread t = new Thread();
t.start();

否则不会启动新线程，您将在同一个线程中执行run方法

无法从事件调度程序线程调用方法

1 个答案: