Question

我让自己成为一个Hangman游戏，基本上我遇到的唯一问题是，每次我猜一封新信时，这些字母都会加倍。例如，如果单词是＆＃34; Hello World＆＃34;我猜到了＃34; l＆＃34;它会打印出来＆＃34; _ _ l l _ _ _ _ l _＆＃34;，对，然后如果我猜＆＃34; w＆＃34;接下来，它打印＆＃34; H _ _ _ l _ l _ _ _ _ _ _ _ _ _ l _ _ _＆＃34; （这是hheelllloo wwoorrlldd）。

我的代码如下所示。我的想法是，因为我有一个嵌套的for循环，但我不知道我还能做些什么。

// This checks previous letters given through String guessedlet.

for(int spot = 0; spot < wrd[0].length(); spot++)
{
    for (int spot2 = 0; spot2 <= guessedlet.length() - 1; spot2++)
    {
        char Spot = wrd[0].charAt(spot);
        String wordletter = Character.toString(Spot);
        char Spot2 = guessedlet.charAt(spot2);
        String guessedletter = Character.toString(Spot2);
        for(int spot3 = 0; spot3 < guessedlet.length(); spot3++)
        {
            char Spot3 = guessedlet.charAt(spot3);
            String guessedletter2 = Character.toString(Spot3);
            if(letter.equals(guessedletter2))
            {
                break;
            }
        }
        if(guessedletter.equals(wordletter))
        {
            wordletter = guessedletter;
        }
        else if(guessedletter.equals(" "))
        {
            wordletter = "";
        }
        else if(!(guessedletter.equals(wordletter)))
        {
            wordletter = "_";
        }
        out.print(wordletter + " ");
    }
}

为什么这些字母是重复的？

Answer 1

您需要将输出移出内部循环，如下所示：

for(int spot = 0; spot < wrd[0].length(); spot++)
{
    String tempDisplay = "_";
    for (int spot2 = 0; spot2 <= guessedlet.length() - 1;      spot2++)
    {
        char Spot = wrd[0].charAt(spot);
        String wordletter = Character.toString(Spot);
        char Spot2 = guessedlet.charAt(spot2);
        String guessedletter = Character.toString(Spot2);
        for(int spot3 = 0; spot3 < guessedlet.length(); spot3++)
        {
            char Spot3 = guessedlet.charAt(spot3);
            String guessedletter2 = Character.toString(Spot3);
            if(letter.equals(guessedletter2))
            {
                break;
            }
        }
        if(guessedletter.equalsIgnoreCase(wordletter))
        {
            tempDisplay = guessedletter;
            break;
        }
    }
    out.print(tempDisplay + " ");
}

您只想为wrd[0] ...

中的每个字符输出一次

字母串中的字母意外地加倍

1 个答案: