Question

我目前正在查看前一个开发人员制作的脚本，该脚本是为了查看表，如果id不存在则创建新代码，如果它存在，则覆盖现有代码。

听起来相当简单，但我无法理解Yii如何管理覆盖和新的验证码。它只是添加了新的记录，而不是写作。

  $invitingUser = User::model()->findByPk(Yii::app()->user->id);

        if ($invitingUser->isAttending($eventId)) {
            // Event attending
            $event = Event::model()->findByPk($eventId);

            // 
            // Uncomment the following line if AJAX validation is needed
            $this->performAjaxValidation(array($guestInviteForm));

            if (isset($_POST['GuestInviteForm'])) {
                $guestInviteForm->attributes = $_POST['GuestInviteForm'];

                // Perform Validation
                $valid = $guestInviteForm->validate();

                if ($valid) {
                    // Check if a Verification Code entry for this user already exists
                    $existingVerificationCode = VerificationCode::model()->findByAttributes(array('user_id' => $user->user_id, 'type' => VerificationCode::TYPE_GUEST_INVITE));


                   //THE CODE ONLY SEEMS TO RUN THIS. 
                    if (is_null($existingVerificationCode)) {
                        // Create Verification Code instance
                        $verificationCode = new VerificationCode();
                        $verificationCode->type = VerificationCode::TYPE_GUEST_INVITE;
                        $verificationCode->user_id = $invitingUser->id;
                        $verificationCode->verification_code = VerificationCode::generateVerificationCode();
                        $verificationCode->forename = $guestInviteForm->forename;
                        $verificationCode->surname = $guestInviteForm->surname;
                        $verificationCode->event_id = $eventId;

                        $verificationCode->save(false);
                    } else {
                        // Update existing Verification Code enty
                        $existingVerificationCode->type = VerificationCode::TYPE_GUEST_INVITE;
                        $existingVerificationCode->user_id = $invitingUser->id;
                        $existingVerificationCode->forename = $guestInviteForm->forename;
                        $existingVerificationCode->surname = $guestInviteForm->surname;
                        $code = $existingVerificationCode->verification_code = VerificationCode::generateVerificationCode();
                        $existingVerificationCode->save(false);
                    }

代码似乎永远不会进入其他地方

//THE CODE ONLY SEEMS TO RUN THIS. 
                        if (is_null($existingVerificationCode)) {
                            // Create Verification Code instance
                            $verificationCode = new VerificationCode();
                            $verificationCode->type = VerificationCode::TYPE_GUEST_INVITE;
                            $verificationCode->user_id = $invitingUser->id;
                            $verificationCode->verification_code = VerificationCode::generateVerificationCode();
                            $verificationCode->forename = $guestInviteForm->forename;
                            $verificationCode->surname = $guestInviteForm->surname;
                            $verificationCode->event_id = $eventId;

                            $verificationCode->save(false);
                        } else {
                            // Update existing Verification Code enty
                            $existingVerificationCode->type = VerificationCode::TYPE_GUEST_INVITE;
                            $existingVerificationCode->user_id = $invitingUser->id;
                            $existingVerificationCode->forename = $guestInviteForm->forename;
                            $existingVerificationCode->surname = $guestInviteForm->surname;
                            $code = $existingVerificationCode->verification_code = VerificationCode::generateVerificationCode();
                            $existingVerificationCode->save(false);
                        }

Answer 1

第一。表单验证后：

if ($valid) {

验证码选择完成：

$existingVerificationCode = VerificationCode::model()->findByAttributes(array('user_id' => $user->user_id, 'type' => VerificationCode::TYPE_GUEST_INVITE));

如果你将它翻译成SQL，它将是这样的：

SELECT * FROM verification_code WHERE user_id=x AND type=x

第二。检查记录是否存在

if (is_null($existingVerificationCode)) {

如果不是 - 创建新的，填充，保存。

其他更新：

$existingVerificationCode->type = VerificationCode::TYPE_GUEST_INVITE;
$existingVerificationCode->user_id = $invitingUser->id;
$existingVerificationCode->forename = $guestInviteForm->forename;
$existingVerificationCode->surname = $guestInviteForm->surname;
$code = $existingVerificationCode->verification_code = VerificationCode::generateVerificationCode();
$existingVerificationCode->save(false);

save(false)表示无需验证即可保存。考虑模型属性 - 数据库表中的字段。

Answer 2

似乎它曾经进入ELSE，因为它永远不会找到$ existingVerificationCode。

我们没有完整的代码，但从我看到的情况来看，我怀疑您是否正在检查错误的用户，因为为$ user搜索事件是很奇怪的，如果并不存在，创建一个与$ invitingUser相关的。

$existingVerificationCode = VerificationCode::model()->findByAttributes(array('user_id' => $user->user_id, 'type' => VerificationCode::TYPE_GUEST_INVITE));
// ...
$verificationCode->user_id = $invitingUser->id;

查看ID时数据库中的条目未被覆盖

2 个答案: