Question

我试图看看输入的lat和long是否与两种类型的多边形中的一种对应，一种是带有Live的键，另一种是带有Soon的键，但是我似乎无法写入if语句。

因此，如果纬度+长点位于多边形类型中，则结果应该是，找到位置并且是实时的。如果纬度+长点是多边形类型很快结果应该是，找到位置并即将到来。如果lat + long不在多边形中，则结果应该是，找不到位置。

我的if语句出了什么问题？

initGeocompleteControl(map, function (result) {
    map.data.forEach(function (f) {
        if (f.getProperty("key") == "live") {

            var bounds = new google.maps.LatLngBounds();
            calcBounds(f.getGeometry(), bounds);

            if (bounds.contains(result.geometry.location)) {
                $( "#result" ).empty();
                $("#result").html('Location is found and is live');
            } else if (f.getProperty("key") == "soon") {
                var bounds = new google.maps.LatLngBounds();
                calcBounds(f.getGeometry(), bounds);

                if (bounds.contains(result.geometry.location)) {
                    $( "#result" ).empty();
                    $("#result").html('Location is found and is coming soon');
                } else {
                    $( "#result" ).empty();
                    $("#result").html('Location is not found');
                }
              //w11 2ed
            }
          // w10 5nr
        }
    });
});

Answer 1

把你的其他条件放在外面即。在if(f.getProperty("key"...之外

initGeocompleteControl(map, function (result) {
map.data.forEach(function (f) {

    if (f.getProperty("key") == "live") {

        var bounds = new google.maps.LatLngBounds();
        calcBounds(f.getGeometry(), bounds);

        if (bounds.contains(result.geometry.location)) {
            $( "#result" ).empty();
            $("#result").html('Location is found and is live');
        }
        //the else if moved from here
    }
    else if
          (f.getProperty("key") == "soon") {

              var bounds = new google.maps.LatLngBounds();
              calcBounds(f.getGeometry(), bounds);

              if (bounds.contains(result.geometry.location)) {
                  $( "#result" ).empty();
                  $("#result").html('Location is found and is coming soon');
              } 
              //else condition moved from here
          } //and else condition after the else if condtion
          else {
                  $( "#result" ).empty();
                  $("#result").html('Location is not found');
          }
              //w11 2ed

          // w10 5nr
     }); 
});

如果声明问题无效

1 个答案: