Question

我需要模拟连续按键。例如，按住＆＃39; c＆＃39;键5秒钟。为了模拟按键事件，我尝试使用CGEventCreateKeyboardEvent：

let event:CGEventRef! = CGEventCreateKeyboardEvent(nil, 8, true)
CGEventPost(CGEventTapLocation.CGSessionEventTap, event)

但它的作用就像是按下按钮然后立即释放。我需要创建一个持续按住按钮（按下键）然后释放它（按键）的事件。

Answer 1

我不确定您要实现的目标，但似乎系统会继续按住该按钮。这个简单的实验表明了这一点。

func applicationDidFinishLaunching(aNotification: NSNotification) {
    print("waiting 4 seconds, use this time to position your cursor in a text field")
    let delayTime = dispatch_time(DISPATCH_TIME_NOW, Int64(4 * Double(NSEC_PER_SEC)))
    dispatch_after(delayTime, dispatch_get_main_queue(), {
        self.insertLetterZ()
    })
}

func insertLetterZ() {
    print("pressing shift")
    self.tapButton(56)

    print("holding button for 2 seconds")
    let delayTime = dispatch_time(DISPATCH_TIME_NOW, Int64(2 * Double(NSEC_PER_SEC)))
    dispatch_after(delayTime, dispatch_get_main_queue(), {
        print("tapping z, but Z will be selected (since shift is still being pressed)")
        self.tapButton(6)

        print("untapping z and shift")
        self.untapButton(6)
        self.untapButton(56)
    })
}

func tapButton(button: CGKeyCode) {
    let event = CGEventCreateKeyboardEvent(nil, button, true)
    CGEventPost(CGEventTapLocation.CGSessionEventTap, event)
}

func untapButton(button: CGKeyCode) {
    let event = CGEventCreateKeyboardEvent(nil, button, false)
    CGEventPost(CGEventTapLocation.CGSessionEventTap, event)
}

如果用户在以编程方式按下shift时点击键盘，则此代码会不大写字母。我还注意到，如果光标位置在shift和z被点击之间被改变，则会插入“z”而不是“Z”

如何模拟连续按键

1 个答案: