Question

我正在尝试使用c中的抽象数据类型编写一个程序，用于基本多项式运算。

到目前为止我已经

了

.h文件

#ifndef Polynomials_ADT_h
#define Polynomials_ADT_h

#include <stdlib.h>

typedef struct poly *Polynomial;

void printPoly(Polynomial);

Polynomial setTerm(int, int);

Polynomial sumPoly(Polynomial, Polynomial);

Polynomial multiPoly (Polynomial, Polynomial);

float evalPoly (Polynomial, float);



#endif

.c实施文件

#include "Polynomials ADT.h"
#include <stdlib.h>


struct poly {int n; int *a;};
Polynomial setTerm (int coeff, int exponent)
{
    int i;
    Polynomial d = malloc(sizeof*d);
    d->a = malloc((exponent+1)*(sizeof(int)));
    d->n = exponent+1;
    d->a[exponent] = coeff;
    for(i=0; i<exponent; i++)
        d->a[i] = 0;
    return d;

}
Polynomial sumPoly(Polynomial r, Polynomial s)
{
    int i; Polynomial d;
    if(r->n < s-> n)
    {
        d = r;
        r = s;
        s = d;

    }

    for (i=0; i< s->n; ++i)
    {
        s-> a[i]+= s-> a[i];
    }

    return s;
}

Polynomial multiPoly (Polynomial s, Polynomial r)
{
    int i, j;
    Polynomial d = setTerm(0, (r->n-1)+ (s->n-1) );
    for (i=0; i < r->n; ++i)
    {
        for(j = 0; j< s->n; ++j)
        {
            d-> a[i+j]+= r->a[i]*s->a[j];
        }
    }
    return d;
}

float evalPoly (Polynomial r, float x)
{
    int i;
    double d = 0.0;
    for (i = r->n-1; i>=0; i--)
    {
        d = d*x + r-> a[i];
    }
    return d;
}

最后我不得不创建我的测试文件来测试我的逻辑

到目前为止，这是我对主要功能所具有的：

  #include <stdio.h>
    #include <stdlib.h>
    #include "Polynomials ADT.h"


   int main()
{
    int i,j;

    Polynomial d =  sumPoly((setTerm(1,2), setTerm(2,3)));

    for (i = 0, x = d; i< n; ++i)
    {
        x = multiPoly(d, x); printPoly(x);

    }
printf("%f", evalPoly(x,r));

}

我的问题是如何打印结果以查看我的实施文件是否有效？我不知道如何显示我的函数的结果，如sumPoly，multiPoly和evalPoly ....请帮忙！

用C编写客户端文件

0 个答案: