我有一台服务器,可以发送数以千计的小文件,如下所示:
static File file = null;
static File temp = null;
private static ServerSocket serverSocket;
private static Socket socket;
public static void main(String[] args) throws FileNotFoundException, IOException
{
serverSocket = new ServerSocket(3000);
socket = serverSocket.accept();
System.out.println("Connected");
File folder = new File("C:...\\Desktop\\thousands_of_tiny_files");
File[] listOfFiles = folder.listFiles();
File result[]=new File[listOfFiles.length];
byte [] bytearray = null;
FileInputStream fin =null;
BufferedInputStream bin = null;
for(int j=0;j<listOfFiles.length;j++){
String path= listOfFiles[j].getPath();
result=sendFile(path);
for(int i=0;i<result.length;i++)
{
fin = new FileInputStream(result[i]);
bin = new BufferedInputStream(fin);
bytearray = new byte [(int)result.length];
bin.read(bytearray,0,bytearray.length);
OutputStream os = socket.getOutputStream();
System.out.println("Sending Files "+ result[i]);
os.write(bytearray,0,bytearray.length);
os.flush();
System.out.println("File transfer completed");
}
}
fin.close();
bin.close();
socket.close();
}
public static File[] sendFile(String path)
{
File folder = new File(path);
File[] listOfFiles = folder.listFiles();
File[] resultt = new File[listOfFiles.length];
for(int i=0;i<listOfFiles.length;i++)
{
temp=listOfFiles[i];
if(temp.isFile() && temp!=null)
resultt[i]=temp;
}
return resultt;
}
它是成功的,但我的问题是在客户端。我不知道如何区分文件并将它们单独写入客户端。
EDIT2: 我使用 ZipOutputStream 更改了服务器端代码,但仍然不知道如何在客户端解压缩和编写(主要是,不知道如何定义 FileOutputStream 在客户端:
for(int i=0;i<result.length;i++)
{
fin = new FileInputStream(result[i]);
bytearray = new byte [(int)result.length];
ZipOutputStream zipOpStream = new ZipOutputStream(socket.getOutputStream());
zipOpStream.putNextEntry(new ZipEntry(result[i].getName()));
System.out.println("Sending Files "+ result[i]);
zipOpStream.write(bytearray,0,bytearray.length);
zipOpStream.flush();
System.out.println("File transfer completed");
}
}
socket.close();
}
和收件人代码:
socket = new Socket("127.0.0.1",3000);
String outDir = "C:...\\Desktop\\here";
BufferedInputStream bis = new BufferedInputStream(socket.getInputStream());
ZipInputStream zips = new ZipInputStream(bis);
ZipEntry zipEntry = null;
while(null != (zipEntry = zips.getNextEntry())){
String fileName = zipEntry.getName();
File outFile = new File(outDir + "/" + fileName);
System.out.println("----["+outFile.getName()+"], filesize["+zipEntry.getCompressedSize()+"]");
if(zipEntry.isDirectory()){
File zipEntryFolder = new File(zipEntry.getName());
if(zipEntryFolder.exists() == false){
outFile.mkdirs();
}
continue;
}else{
File parentFolder = outFile.getParentFile();
if(parentFolder.exists() == false){
parentFolder.mkdirs();
}
}
System.out.println("ZipEntry::"+zipEntry.getCompressedSize());
FileOutputStream fos = new FileOutputStream(outFile);
int fileLength = (int)zipEntry.getSize();
byte[] fileByte = new byte[fileLength];
zips.read(fileByte);
fos.write(fileByte);
fos.close();
socket.close();
}
现在我得到了一个特殊情况&#34;负面 NegativeArraySizeException &#34;
Exception in thread "main" java.lang.NegativeArraySizeException
at recieve.Reciever.<init>(Reciever.java:71)
at recieve.Recieve$1.<init>(Recieve.java:28)
at recieve.Recieve.main(Recieve.java:28)
ZipEntry::-1
可能是因为
int fileLength = (int)zipEntry.getSize();
但我怎么解决这个问题呢?我需要zip文件夹的下一个条目的siz用于写入文件。 但大小在长而不是 int
答案 0 :(得分:1)
如何将其写入ZipOutputStream,您可以在另一侧将文件作为单个流接收。获得完整输出后,可以编写反向代码来缩小zip文件并获取所有文件。提供用于将Zip写入套接字流的示例代码,您可以构建代码。
请参阅this length,了解使用ZipOutputStream发送文件的示例服务器和客户端实现Stick2Code