Question

我有2个词典：

data1 = [
{key1: 1, key2: 1, count:  3},
{key1: 2, key2: 1, count: 15},
{key1: 3, key2: 1, count: 12},
{key1: 1, key2: 2, count: 13},
{key1: 2, key2: 2, count:  8},
]

data2 = [
key1:{1: 'value1_1', 2: 'value1_2', 3: 'value1_3'},
key2:{1: 'value2_1', 2: 'value2_2'},
]

我想将这两个词典合并为一个大字典，看起来像这样：

new_data = [
{key1: 1, key1_name: 'value1_1', key2: 1, key2_name: 'value2_1', count:  3},
{key1: 2, key1_name: 'value1_2', key2: 1, key2_name: 'value2_1', count: 15},
{key1: 3, key1_name: 'value1_3', key2: 1, key2_name: 'value2_1', count: 12},
{key1: 1, key1_name: 'value1_1', key2: 2, key2_name: 'value2_2', count: 13},
{key1: 2, key1_name: 'value1_2', key2: 2, key2_name: 'value2_2', count:  8},
{key1: 3, key1_name: 'value1_3', key2: 2, key2_name: 'value2_2', count:  0},
]

或者也许，就像那样：

new_data2 = [
{key1: {
value: 1, name: 'value1_1',
data: [
{value: 1, name: 'value2_1', count:   3},
{value: 2, name: 'value2_2', count:  13},
]},
{key1: {
value: 2, name: 'value1_2',
data: [
{value: 1, name: 'value2_1', count:  15},
{value: 2, name: 'value2_2', count:   8},
]},
{key3: {
value: 2, name: 'value1_3',
data: [
{value: 1, name: 'value2_1', count:  12},
{value: 2, name: 'value2_2', count:   0},
]}]

注1：请注意每个合并的字典都有一个额外的行，其中key1 = 3，键2 = 2，这个组合在＆＃39中没有值; DATA2＆＃39; dict，因此分配给该行的计数值为0.

注2：我不确定＆＃34;更好＆＃34;表示我的数据的方式，如new_data1或new_data2。

注3：我想尽可能地使其通用，我不能假设级别数（在这种情况下是2级，key1和key2）将被修复，所以我需要允许更多级别，这意味着能够处理3级甚至4级。例如（有3个级别）：

data = [
{key1: 1, key1_name: 'value1_1', key2: 1, key2_name: 'value2_1', key3: 1, key3_name: 'value3_1', count:  3},
{key1: 1, key1_name: 'value1_1', key2: 1, key2_name: 'value2_1', key3: 2, key3_name: 'value3_2', count:  2},
{key1: 1, key1_name: 'value1_1', key2: 2, key2_name: 'value2_2', key3: 1, key3_name: 'value3_1', count:  1},
{key1: 1, key1_name: 'value1_1', key2: 2, key2_name: 'value2_2', key3: 2, key3_name: 'value3_2', count:  6},
]

任何帮助将不胜感激。感谢

Answer 1

你可以试试这个：

key2_name = "key2_name"
key1_name = "key1_name"
key3_name = "key3_name"
data1 = [
    {key1: 1, key2: 1, count:  3},
    {key1: 2, key2: 1, count: 15},
    {key1: 3, key2: 1, count: 12},
    {key1: 1, key2: 2, count: 13},
    {key1: 2, key2: 2, count:  8}
]

data2 = { key1:{1: 'value1_1', 2: 'value1_2', 3: 'value1_3'}, key2:{1: 'value2_1', 2: 'value2_2'}
}

for dict_ in data1:
    dict_["key1_name"] = data2[key1][dict_[key1]]
    dict_["key2_name"] = data2[key2][dict_[key2]]

# equivalent to:
for dict_ in data1:
    for k, v in (key1_name, key1), (key2_name, key2):
        dict_[k] = data2[v][dict_[v]]

打印（DATA1）

[{'count': 3, 'key2': 1, 'key1': 1, 'key2_name': 'value2_1', 'key1_name': 'value1_1'},
            {'count': 15, 'key2': 1, 'key1': 2, 'key2_name': 'value2_1', 'key1_name': 'value1_2'},
            {'count': 12, 'key2': 1, 'key1': 3, 'key2_name': 'value2_1', 'key1_name': 'value1_3'},
            {'count': 13, 'key2': 2, 'key1': 1, 'key2_name': 'value2_2', 'key1_name': 'value1_1'},
            {'count': 8, 'key2': 2, 'key1': 2, 'key2_name': 'value2_2', 'key1_name': 'value1_2'}]

[编辑3键示例]

data1 = [
    {key1: 1, key2: 1, key3: 1, count:  3},
    {key1: 2, key2: 1, key3: 1, count: 15},
    {key1: 3, key2: 1, key3: 1, count: 12},
    {key1: 1, key2: 2, key3: 1, count: 13},
    {key1: 2, key2: 2, key3: 2, count:  8}
]
data2 = { key1:{1: 'value1_1', 2: 'value1_2', 3: 'value1_3'},
          key2:{1: 'value2_1', 2: 'value2_2'},
          key3:{1: 'value3_1', 2: 'value3_2'}
}
keys_name = [("%s_name"%v, v) for v in data2.keys()]
for dict_ in data1:
    for k, v in keys_name:
        dict_[k] = data2[v][dict_[v]]

按字母顺序排列词典

1 个答案: