Question

我在这里有这个解析树：

我想要的是从一个共同的父母那里得到所有的单词，在一个子树的子集中给出一个单词。例如，如果你采用＆＃34; 瓶子＆＃34;然后我想得到＆＃34; Voss瓶＆＃34;或者甚至＆＃34; Voss瓶装水＆＃34;但我不知道该怎么做。

Annotation document = new Annotation(sentenceText); 
this.pipeline.annotate(document);

List<CoreMap> sentences = document.get(SentencesAnnotation.class);

for (CoreMap sentence : sentences) {

    Tree tree = sentence.get(TreeAnnotation.class);

    List<Tree> leaves = new ArrayList<>();
    leaves = tree.getLeaves(leaves);

    for (Tree leave : leaves) {         
        String compare = leave.toString().toLowerCase();            
        if(compare.equals(word) == true) {
            // Get other nodes in the same subtree
        }
    }
}

调用leave.parent()不起作用。我也尝试tree.parent(leave)，但这也不起作用（返回null）。

我也试过

for (Tree leave : tree) {
    String compare = leave.toString().toLowerCase();        
    if(compare.equals(word) == true) {
        // ..
    }
}

但我也一样。

public Tree parent(Tree root)
返回树节点的父节点。此例程将从给定的根遍历树（深度优先），并且无论具体类是否存储父类，都将正确地找到父树。如果此节点是根节点，或者此节点未包含在以root为根的树中，则它将仅返回null。

我怎样才能做到这一点？ #EverythingIsBrokenAllTheTime

Answer 1

此示例行应该为给定的单词提供两个级别（请注意，POS标记有节点，因此您需要执行两次父级;第一个父级返回以POS标记为根的子树）

Tree root = (leave.parent(tree)).parent(tree);

“leave”应该是该单词的节点 “树”应该是整个句子的树

此方法从根开始遍历树，跟踪它通过的节点。当它命中你想要的节点时（在这个例子中“离开”），它返回适当的父节点。

完整代码：

import java.io.*;
import java.util.*;
import edu.stanford.nlp.io.*;
import edu.stanford.nlp.ling.*;
import edu.stanford.nlp.pipeline.*;
import edu.stanford.nlp.trees.*;
import edu.stanford.nlp.trees.TreeCoreAnnotations.*;
import edu.stanford.nlp.semgraph.*;
import edu.stanford.nlp.ling.CoreAnnotations.*;
import edu.stanford.nlp.util.*;

public class RootFinderExample {

    public static void main (String[] args) throws IOException {
        // build pipeline
        Properties props = new Properties();
        props.setProperty("annotators","tokenize, ssplit, pos, lemma, ner, parse");
        StanfordCoreNLP pipeline = new StanfordCoreNLP(props);
        String text = "We were offered water for the table but were not told the Voss bottles of water were $8 a piece.";
        Annotation annotation = new Annotation(text);
        pipeline.annotate(annotation);
        List<CoreMap> sentences = annotation.get(SentencesAnnotation.class);
        for (CoreMap sentence : sentences) {
            Tree tree = sentence.get(TreeAnnotation.class);
            List<Tree> leaves = new ArrayList<>();
            leaves = tree.getLeaves(leaves);
            for (Tree leave : leaves) {
                String compare = leave.toString().toLowerCase();
                if(compare.equals("bottles") == true) {
                    System.out.println(tree);
                    System.out.println("---");
                    System.out.println(leave);
                    System.out.println(leave.parent(tree));
                    System.out.println((leave.parent(tree)).parent(tree));
                }
            }

        }
    }

}

如何在Stanford Parse-Tree中获取根节点？

1 个答案: