XML Oracle:从多个重复的子节点中提取特定属性

时间:2016-01-21 13:40:03

标签: sql xml oracle plsql

我无法理解我看到的其他问题,因为它们有点不同。

我从Web服务vi UTL_HTTP获取XML作为响应。 XML具有重复的子节点,我只想提取1个特定值。

响应XML:

<Customer>
    <Loyalty>
       <Client>
          <Identifications>
              <Identification>
                   <Form>Form1</Form>
                   <value>1234</value>
              </Identification>
              <Identification>
                   <Form>Form2</Form>
                   <value>4442</value>
              </Identification>
              <Identification>
                   <Form>Form3</Form>
                   <value>9995</value>
              </Identification>
           </Identifications>
       </Client>
    </Loyalty>
 </Customer>

我只需要在节点<value> =&#34; Form3&#34;。

的地方提取节点<Form>

因此,在我的代码中,我收到另一个函数的响应

v_ds_xml_response XMLTYPE;
-- Here would lie the rest of the code (omitted) preparing the XML and next calling the function with    it:

V_DS_XML_RESPONSE := FUNCTION_CALL_WEBSERVICE(
      P_URL => V_DS_URL, --endpoint
      P_DS_XML => V_DS_XML, --the request XML
      P_ERROR => P_ERROR); 

有了这个,我创建了一个LOOP来存储值。我尝试过使用WHERE,甚至创建一个类型(下面的V_IDENTIFICATION是类型),但它没有返回任何内容(null)。

for r IN (
SELECT         
 ExtractValue(Value(p),'/Customer/Loyalty/Client/Identifications/Identification/*[local-name()="Form"]/text()') as form, 
     ExtractValue(Value(p),'/Customer/Loyalty/Client/Identifications/Identification/*[local-name()="value"]/text()') as value
   FROM   TABLE(XMLSequence(Extract(V_DS_XML_RESPONSE,'//*[local-name()="Customer"]'))) p

LOOP
V_IDENTIFICATION.FORM   := r.form;
V_IDENTIFICATION.VALUE  := r.value;
END LOOP;

SELECT 
       V_IDENTIFICATION.VALUE
INTO   
       P_LOYALTY_VALUE
FROM   dual
WHERE  V_IDENTIFICATION.TIPO = 'Form3';

注意,P_LOYALTY_VALUE是我的程序

中的OUT参数

4 个答案:

答案 0 :(得分:2)

使用此sql,您应该获得所需的值:

with data as
 (select '<Customer>
   <Loyalty>
   <Client>
      <Identifications>
          <Identification>
               <Form>Form1</Form>
               <value>1234</value>
          </Identification>
          <Identification>
               <Form>Form2</Form>
               <value>4442</value>
          </Identification>
          <Identification>
               <Form>Form3</Form>
               <value>9995</value>
          </Identification>
       </Identifications>
   </Client>
</Loyalty>
</Customer>' as xmlval
    from dual b)
 (SELECT t.val
    FROM data d,
         xmltable('/Customer/Loyalty/Client/Identifications/Identification'
                  PASSING xmltype(d.xmlval) COLUMNS 
                  form VARCHAR2(254) PATH './Form',
                  val VARCHAR2(254) PATH './value') t
   where t.form = 'Form3');

答案 1 :(得分:1)

当你不知道确切的路径时。

select * from 
xmltable('for $i in $doc//*/Form
 where $i = "Form2"
 return $i/../value'
passing 
xmltype('<Customer>
    <Loyalty>
       <Client>
          <Identifications>
              <Identification>
                   <Form>Form1</Form>
                   <value>1234</value>
              </Identification>
              <Identification>
                   <Form>Form2</Form>
                   <value>4442</value>
              </Identification>
              <Identification>
                   <Form>Form3</Form>
                   <value>9995</value>
              </Identification>
           </Identifications>
       </Client>
    </Loyalty>
 </Customer>') as "doc" ) 

答案 2 :(得分:1)

要提取您要查找的值,可以使用以下XPATH表达式:

/Customer/Loyalty/Client/Identifications/Identification/Form[text()='Form3']/../value

Test it here

然后你可以使用XMLTABLE函数来获得结果

SELECT my_value
FROM xmltable(
        '/Customer/Loyalty/Client/Identifications/Identification/Form[text()=''Form3'']/../value'
        PASSING xmltype(
'<Customer>
    <Loyalty>
        <Client>
        <Identifications>
            <Identification>
                <Form>Form1</Form>
                <value>1234</value>
            </Identification>
            <Identification>
                <Form>Form2</Form>
                <value>4442</value>
            </Identification>
            <Identification>
                <Form>Form3</Form>
                <value>9995</value>
            </Identification>
        </Identifications>
        </Client>
    </Loyalty>
</Customer>')
        COLUMNS
            my_value VARCHAR2(4000) path '/value'
    )

答案 3 :(得分:0)

Aaand我设法找到了解决方案,这很简单,只需添加[text()=&#34; Form3&#34;] /.../"在

中预测Xpath
SELECT         
ExtractValue(Value(p),'/Customer/Loyalty/Client/Identifications/Identification/*[local-name()="Form"][text()="Form3"]/text()') as form, 
 ExtractValue(Value(p),'/Customer/Loyalty/Client/Identifications/Identification/Form[text()="Form3"]/.../*[local-name()="value"]/text()') as value

还提取了将它们直接发送到过程的OUT参数中的值:

P_FORM := r.form;
P_LOYALTY_VALUE := r.value;