Question

我有一个xml代码：

<begin>
    <entry>
        <lastname>gordon</lastname>
        <NumberList>
            <number>100</number>
            <codelist>
                 <code>213</code>
                 <code>214</code>
            <codelist>
            <login>
                 <user>user1</user>
                 <user>user2</user>
            </login>
        <NumberList>
        <address>
            <addresslist>Jl. jalan pelan-pelan ke Bekasi, Indonesia</addresslist>
        </address>
    </entry>
    <entry>
        <lastname>mark</lastname>
        <address>
            <addresslist>Jl. jalan cepet-cepet ke Jakarta, Indonesia</addresslist>
        </address>
    </entry>
</begin>

我的代码：

FOR r IN (SELECT VALUE(p) col_val,
                 EXTRACT(VALUE(P), '/entry/codelist') AS code,
                 EXTRACT(VALUE(P), '/entry/login') AS login
           FROM TABLE(XMLSequence(Extract(x,'/begin/entry'))) p)
LOOP
   IF r.col_val.existsnode('/entry/lastname/text()') > 0 
   THEN
      vc_lastname := r.col_val.extract('/sdnEntry/lastname/text()').getstringval();
   END IF;

   IF r.col_val.existsnode('/entry/address/addresslist/text()') > 0 
   THEN
    vc_address := r.col_val.extract('/sdnEntry/address/addresslist/text()').getstringval();
   END IF;

   IF r.col_val.existsnode('/entry/codelist/id/code/text()') > 0 AND r.col_val.existsnode('/entry/login/user/text()') > 0 
   THEN
      FOR R1 IN (SELECT EXTRACTVALUE(VALUE(T1), '/codelist/code/text()') AS code
                   FROM TABLE(XMLSEQUENCE(EXTRACT(R.code, '/codelist'))) T1)
      LOOP
         DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName||' - '||R1.code||' - '||R2.address);
      END LOOP;

      FOR R2 IN (SELECT
                        EXTRACTVALUE(VALUE(T1), '/login/user/text()') AS user
                   FROM TABLE(XMLSEQUENCE(EXTRACT(R.address, 'login/'))) T1)
      LOOP
         DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName||' - '||R2.user||' - '||R2.address);
      END LOOP;
  ELSE
        DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName);
  END IF;

我的问题：如何循环子节点，使数据变为这样：

LastName | Number | code    | user  |   address
gordon   | 100    | 213     | user1 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon   | 100    | 213     | user2 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon   | 100    | 214     | user1 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon   | 100    | 214     | user2 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
mark     | Null   | null    | null  |Jl. jalan cepet-cepet ke Jakarta, Indonesia

任何帮助都会受到赞赏。

Answer 1

您可以使用XMLTable()功能

来获得所需的结果

select q.Lastname
     , q.Numberid
     , s.codeid
     , w.LoginId
     , q.address
  from t1 t
  left join xmltable('/begin/entry'
                      passing t.xml_col 
                      columns LastName   varchar2(21)  path 'lastname',
                              NumberId   number        path 'NumberList/number',
                              Address    varchar2(201) path 'address/addresslist',
                              CodeList   XmlType       Path 'NumberList/codelist/code',
                              Logins     XmlType       Path 'NumberList/login/user'
                      ) q
    on (1=1) 
  left join xmltable('/code'
                      passing q.CodeList
                      columns CodeId number path '.') s
    on (1=1)
  left join   xmltable('/user'
                        passing q.Logins
                        columns LoginId varchar2(11) path '.') w
    on (1=1)

结果：SQLFiddle Demo

Lastname Numberid Codeid Loginid Address 
---------------------------------------------------------------------------
gordon   100      213    user1   Jl. jalan pelan-pelan ke Bekasi, Indonesia 
gordon   100      213    user2   Jl. jalan pelan-pelan ke Bekasi, Indonesia 
gordon   100      214    user1   Jl. jalan pelan-pelan ke Bekasi, Indonesia 
gordon   100      214    user2   Jl. jalan pelan-pelan ke Bekasi, Indonesia 
mark     null     null   null    Jl. jalan cepet-cepet ke Jakarta, Indonesia

Find out more关于XMLTable()功能。

注意：使用11.2.0.2之前的Oracle版本，当ORA-1780 error参数设置为cursor_sharing时，您可能会遇到FORCE（错误8545377）某些类型的XML查询SIMILAR或cursor_sharing（从11.2开始弃用）。将EXACT参数设置为{{1}}（默认值）将解决问题。

XML Oracle：多子节点提取

1 个答案: