Question

如何将简单游戏的尝试限制为仅三次？我认为你会使用布尔值。但不确定。

import java.util.Scanner;

public class guess {

    public static void main(String[] args) {
        int randomN = (int) (Math.random() * 10) + 1;

        Scanner input = new Scanner(System.in);
        int guess;
        System.out.println("Enter a number between 1 and 10.");
        System.out.println();

        do {
            System.out.print("Enter your guess: ");
            guess = input.nextInt();

            if (guess == randomN) {
                System.out.println("You won!");
            } else if (guess > randomN) {
                System.out.println("Too high");
            } else if (guess < randomN) {
                System.out.println("Too low");
            } 
        } while (guess != randomN);
    }
}

Answer 1

#ifdef _MSC_VER
  // Map to equivalent function
  #define snprintf sprintf_s
#endif

Answer 2

使用旗帜。将其初始化为0.如果猜测正确，则将其重置为0.如果不增加1.在每次猜测之前，检查标志是否>如果没有让继续，如果是的话。

Answer 3

您可以在猜测失败期间递增。我相信变量应该位于循环之外。然后剩下的就是添加一个部分，在猜测用完时通知用户失败。

public static void main(String[]args) {
    int rNumber = (int)(Math.random() * 10) + 1;
    Scanner input = new Scanner(System.in);
    int guess;
    int tries = 0;
    int success = 0;

    System.out.println("Enter a number between 1 and 10.");
    System.out.println();
    do {
        System.out.println("Enter your guess: ");
        guess = input.nextInt();
        if(guess == rNumber) {
            System.out.println("You guessed right! You win!");
            success++;
        } else if (guess < rNumber) {
            System.out.println("Too low");
            tries++;
        } else if (guess > rNumber) {
            System.out.println("Too high.");
            tries++;
        }
    } while(tries != 3 && success != 1 || success != 1);

}

尝试简单游戏的次数有限？

3 个答案: