所以这项计划我的工作。我可以从开始日期到结束日期获取日期列表。但这是很多代码。我想知道是否有更简单的方法来做同样的事情。任何可以给予的帮助表示赞赏。
start_date = 20151002 # < 10-02-2015
dates = []
end_date = 20170304 # 03-04-2017
def nextday():
global start_date
while start_date < end_date:
start_date += 1
next_date = str(start_date)
dates.append(start_date)
#so with the date the first 4 characters is the year
#the next two charcters is the month
#The last two charcters is the day.
#str(start_date)[4:] should actually be the month and the day.
if str(next_date)[4] + str(next_date)[5] == "10" and str(next_date)[6] + str(next_date)[7] == "31":#< there are only 31 days in oct - 10
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "1", "1", "0", "1"]
print "Nov"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
if str(next_date)[4] + str(next_date)[5] == "11" and str(next_date)[6] + str(next_date)[7] == "30": #< there are only 30 days in nov - 11
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "1", "2", "0", "1"]
print "Dec"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
if str(next_date)[4] + str(next_date)[5] == "12" and str(next_date)[6] + str(next_date)[7] == "31": #< there are only 31 days in dec - 12
#^ This month will also change the year.
date_list = [next_date[0], next_date[1], next_date[2], str(int(next_date[3]) + 1), "0","1","0","1"]
print "Jan", "New year"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
if str(next_date)[4] + str(next_date)[5] == "01" and str(next_date)[6] + str(next_date)[7] == "31": #< there are only 31 days in jan - 01
#^ This month will also change the year.
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "0","2","0","1"]
print "Feb"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
if int(next_date[0]+next_date[1]+next_date[2]+next_date[3]) % 4 == 0:
if str(next_date)[4] + str(next_date)[5] == "02" and str(next_date)[6] + str(next_date)[7] == "29": #< there are only 29 days in LEAP YEAR feb - 02
#^ This month will also change the year.
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "0","3","0","1"]
print "Mar"
new_month = ""
for dat in date_list: ####################LEAP YEAR#################
new_month += dat
start_date = int(new_month)
else:
if str(next_date)[4] + str(next_date)[5] == "02" and str(next_date)[6] + str(next_date)[7] == "28": #< there are only 28 days in feb - 02
#^ This month will also change the year.
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "0","3","0","1"]
print "Mar"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
if str(next_date)[4] + str(next_date)[5] == "03" and str(next_date)[6] + str(next_date)[7] == "31": #< there are only 29 days in mar - 03
#^ This month will also change the year.
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "0","4","0","1"]
print "Apr"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
if str(next_date)[4] + str(next_date)[5] == "04" and str(next_date)[6] + str(next_date)[7] == "30": #< there are only 30 days in apr - 04
#^ This month will also change the year.
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "0","5","0","1"]
print "May"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
if str(next_date)[4] + str(next_date)[5] == "05" and str(next_date)[6] + str(next_date)[7] == "31": #< there are only 31 days in may - 05
#^ This month will also change the year.
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "0","6","0","1"]
print "Jun"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
if str(next_date)[4] + str(next_date)[5] == "06" and str(next_date)[6] + str(next_date)[7] == "30": #< there are only 30 days in jun - 0
#^ This month will also change the year.
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "0","7","0","1"]
print "Jul"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
if str(next_date)[4] + str(next_date)[5] == "07" and str(next_date)[6] + str(next_date)[7] == "31": #< there are only 31 days in jul - 0
#^ This month will also change the year.
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "0","8","0","1"]
print "Aug"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
if str(next_date)[4] + str(next_date)[5] == "08" and str(next_date)[6] + str(next_date)[7] == "31": #< there are only 31 days in aug - 0
#^ This month will also change the year.
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "0","9","0","1"]
print "Sept"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
if str(next_date)[4] + str(next_date)[5] == "09" and str(next_date)[6] + str(next_date)[7] == "30": #< there are only 31 days in sep - 0
#^ This month will also change the year.
date_list = [next_date[0], next_date[1], next_date[2], next_date[3], "1","0","0","1"]
print "Oct"
new_month = ""
for dat in date_list:
new_month += dat
start_date = int(new_month)
print start_date
nextday()
print dates
答案 0 :(得分：2)
您需要的所有功能都已包含在标准库中。
import datetime
start = datetime.date(2015, 10, 2)
end = datetime.date(2017, 3, 4)
current = start
dates = []
while current <= end:
dates.append(str(current))
current += datetime.timedelta(days=1)
答案 1 :(得分：2)
我希望，它会对你有所帮助：
import datetime
start_date = datetime.datetime(2015, 10, 02)
end_date = datetime.datetime(2017, 03, 04)
def nextday():
global start_date
start_date += datetime.timedelta(days=1)
return min(start_date, end_date)
>>> start_date
datetime.datetime(2015, 10, 2, 0, 0)
>>> nextday()
datetime.datetime(2015, 10, 3, 0, 0)
>>> nextday()
datetime.datetime(2015, 10, 4, 0, 0)
>>> nextday()
datetime.datetime(2015, 10, 5, 0, 0)
>>> nextday()
datetime.datetime(2015, 10, 6, 0, 0)
答案 2 :(得分：1)
您可以使用datetime和timedelta每天从start_date到end_date进行迭代。
以下是将start_date增加一天的方法：
from datetime import date
from datetime import timedelta
one_day = timedelta(days=1)
start_date = date(2015, 10, 2)
print(start_date)
print(start_date + one_day)
然后你会循环直到你到达end_date。
答案 3 :(得分：1)
使用datetime模块：
import datetime
day = datetime.timedelta(days=1)
start = datetime.datetime(2015, 10, 3)
end = datetime.datetime(2017, 3, 5)
times = [start + day * x for x in range((end - start).days)]
创建：
>>> times
[datetime.datetime(2015, 10, 3, 0, 0),
datetime.datetime(2015, 10, 4, 0, 0),
...
datetime.datetime(2017, 3, 3, 0, 0),
datetime.datetime(2017, 3, 4, 0, 0)]