我想在一个单独的线程中运行Python serversocket类。为此,我修改了此代码以支持python线程:
原始文件
import SocketServer
class MyTCPHandler(SocketServer.BaseRequestHandler):
def handle(self):
self.data = self.request.recv(1024).strip()
print self.data
if __name__ == "__main__":
HOST, PORT = "192.168.65.1", 5001
server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler)
server.serve_forever()
到我的档案:
import SocketServer
class MyTCPHandler(SocketServer.BaseRequestHandler):
def __init__(self):
self._running = True
def terminate(self):
self._running = False
def setup(self):
print('{}:{} connected'.format(*self.client_address))
def handle(self):
self.data = self.request.recv(1024).strip()
print self.data
def finish(self):
print('{}:{} disconnected'.format(*self.client_address))
#if __name__ == "__main__":
def run(self):
HOST, PORT = "192.168.65.1", 5001
server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler)
server.serve_forever()
我使用
在主文件中将其作为单独的主题运行Thread(target=MyTCPHandler().run, args=()).start()
但是,当我运行主python文件时出现此错误
----------------------------------------
Exception happened during processing of request from ('192.168.65.1', 37997)
----------------------------------------
Traceback (most recent call last):
File "/usr/lib/python2.7/SocketServer.py", line 295, in _handle_request_noblock
self.process_request(request, client_address)
File "/usr/lib/python2.7/SocketServer.py", line 321, in process_request
self.finish_request(request, client_address)
File "/usr/lib/python2.7/SocketServer.py", line 334, in finish_request
self.RequestHandlerClass(request, client_address, self)
TypeError: __init__() takes exactly 1 argument (4 given)
首先,我对支持线程的修改是否正确? 拜托,有人可以帮个忙吗?
答案 0 :(得分:1)
这里的问题是你将不正确数量的参数传递给SocketServer.BaseRequestHandler中的Parent方法。
了解kargs和inheritance,您就会明白这个问题。简而言之,kargs可以采用可变数量的参数。
希望它有所帮助。 改变
def __init__(self):
self._running = True
到
def __init__(self, *kargs):
SocketServer.BaseRequestHandler.__init__(self, *kargs)
self._running = True