Question

所以在将一些用户输入保存到数据库之前，我已经完成了大量的例行计算。

    $cData['cCashFlow'] = $uData['uMonthlyIncome'] - $uData['uMonthlyExpenses'];
    $cData['cLiquidAssets'] = $uData['uCashSavings'] + $uData['uRetirementSavings'] + $uData['uOtherInvestments'];
    $cData['cDebt'] = $uData['uStudentLoans'] + $uData['uCreditCardDebt'] +$uData['uAutoLoanDebt'] + $uData['uOtherDebt'];
    $cData['cConsumerDebt'] = $uData['uCreditCardDebt'] + $uData['uAutoLoanDebt'] + $uData['uOtherDebt'];
    $cData['cLiquidNetWorth'] = $cData['cLiquidAssets'] - $cData['cDebt'];
    $cData['cMonthlyDebt'] = $uData['uStudentLoanPayments'] + $uData['uAutoLoanPayments'] + $uData['uCreditCardPayments'] + $uData['uOtherDebtPayments'];
    $cData['cHomeEquity'] = $uData['uHomeValue'] - $uData['uMortgageBalance'];
    $cData['cNetWorth'] = $cData['cLiquidNetWorth'] + $cData['cHomeEquity'];

$cData是计算数据，$uData来自用户。

有些计算不会在每次保存时执行，因为用户可能没有填写所有字段。

当然我可以用条件包装每个计算：

if($uData['uMonthlyIncome'] && $uData['uMonthlyExpenses']) :
    $cData['cCashFlow'] = $uData['uMonthlyIncome'] - $uData['uMonthlyExpenses'];
endif;

但它只是非常麻烦和劳动密集型，特别是如果我必须添加更多这些计算。

只有当计算中的所有变量都存在时，是否有一种简单的方法来执行这样的计算？

Answer 1

您可以通过将条件包装到函数中来使条件更具语义性（期望它在类中）：

private $uData;

private function isFilled()
{
    // get all function arguments as an array
    $args = func_get_args();
    // check each argument as an index to uData is empty 
    foreach ($args as $arg) {
        if (empty($this->uData[$arg])) {
            return false;
        }
    }
    return true;
}

public function process()
{
    $this->uData = $uData;

    if ($this->isFilled('uMonthlyIncome', 'uMonthlyExpenses')) {
        // do the calculations
         $cData['cCashFlow'] = $this->uData['uMonthlyIncome'] - $this->uData['uMonthlyExpenses'];
    }
}

Answer 2

如果关键是要保留可读代码，你可以使用内联条件并使用对齐来摆脱混乱..

$cData['cCashFlow']     = isset($uData['uMonthlyIncome']) && !empty($uData['uMonthlyIncome']) ? $uData['uMonthlyIncome'] - $uData['uMonthlyExpenses']                               : null;
$cData['cLiquidAssets'] = isset($uData['uCashSavings'])   && !empty($uData['uCashSavings'])   ? $uData['uCashSavings'] + $uData['uRetirementSavings'] + $uData['uOtherInvestments'] : null;

还是干净吧？如上所述，您可以将条件包装在一个函数中，该函数接收必须检查的键并返回一个布尔值。

Answer 3

这是我最终做的事情：

我构建了一个回调函数来补充array_sum：

function array_subtract($array){
  $result = $array[0];
  foreach($array as $key => $value) :
    if($key !== 0) :
      $result -= $value;
    endif;
  endforeach;

  return $result;
}

然后，我构建了一个函数来检查所有输入变量，然后在所有输入都存在的情况下处理计算：

public function calculator($function, $args){
  foreach ($args as $arg) :
    if($arg === null) :
      return null;
    endif;
  endforeach;

  return $function($args);
}

然后我调用了“checker”函数并将回调函数和数据作为数组输入：

$cData['cCashFlow'] = $this->calculator('array_subtract', array($uData['uMonthlyIncome'], $uData['uMonthlyExpenses']));
$cData['cLiquidAssets'] = $this->calculator('array_sum', array($uData['uCashSavings'], $uData['uRetirementSavings'], $uData['uOtherInvestments']));
$cData['cDebt'] = $this->calculator('array_sum', array($uData['uStudentLoans'], $uData['uCreditCardDebt'], $uData['uAutoLoanDebt'], $uData['uOtherDebt']));
$cData['cConsumerDebt'] = $this->calculator('array_sum', array($uData['uCreditCardDebt'] + $uData['uAutoLoanDebt'] + $uData['uOtherDebt']));
$cData['cLiquidNetWorth'] = $this->calculator('array_subtract', array($cData['cLiquidAssets'], $cData['cDebt']));
$cData['cMonthlyDebt'] = $this->calculator('array_sum', array($uData['uStudentLoanPayments'], $uData['uAutoLoanPayments'], $uData['uCreditCardPayments'], $uData['uOtherDebtPayments']));
$cData['cHomeEquity'] = $this->calculator('array_subtract', array($uData['uHomeValue'], $uData['uMortgageBalance']));
$cData['cNetWorth'] = $this->calculator('array_sum', array($cData['cLiquidNetWorth'], $cData['cHomeEquity']));

如果每个计算的所有输入值都不存在，则NULL将存储到数据库中，这正是我想要的。

Answer 4

尝试这样的事情

<?php
$uData = array();
@$uData['bla'] = $_POST['bla'];
@$uData['blaa'] = $_POST['blaa'];
@$uData['blaaa'] = $_POST['blaaa'];

$userInputs = array('bla', 'blaa', 'blaaa');

function checkUserInput($Inputs, $uData){
foreach($Inputs as $value){
    if($uData[$value] == null){
         return false;
    }
}
return true;
}

if(checkUserInput($userInputs, $uData) == true)
{
    echo "All here!";
}

PHP：仅在所有变量都存在的情况下执行计算 - 不使用条件

4 个答案: