Question

我正在尝试计算 N行的移动平均值，单个查询中的所有行。在示例中，我试图计算50行的移动平均值。

SELECT h1.date, h1.security_id, ( SELECT AVG(last50.close) FROM ( SELECT h.close FROM history as h WHERE h.date <= h1.date AND h.security_id = h1.security_id ORDER BY h.date DESC LIMIT 50 ) as last50 ) as avg50 FROM history as h1

但是，MySQL在运行此查询时出错：

Unknown column 'h1.date' in 'where clause'

我正在尝试这种方法，因为列出的其他解决方案似乎并不适用于我的用例。有一个N 天的移动平均值的解决方案，但由于我的数据集中没有考虑所有日期，我需要N 行的平均值。

This solution（如下所示）不起作用，因为AVG（SUM和COUNT}不会占LIMIT：

SELECT t1.data_date ( SELECT SUM(t2.price) / COUNT(t2.price) FROM t as t2 WHERE t2.data_date <= t1.data_date ORDER BY t2.data_date DESC LIMIT 5 ) AS 'five_row_moving_average_price' FROM t AS t1 ORDER BY t1.data_date;

This question看起来很有希望，但对我来说有些难以理解。

有什么建议吗？ Here's an SQLFiddle来玩。

Answer 1

<强>计划

过去50天的自我加入历史

按日期和安全ID（当前）进行平均分组

<强>查询

select curr.date, curr.security_id, avg(prev.close)
from history curr
inner join history prev 
on prev.`date` between date_sub(curr.`date`, interval 49 day) and curr.`date`
and curr.security_id = prev.security_id
group by 1, 2
order by 2, 1
;

<强>输出

+---------------------------+-------------+--------------------+
|           date            | security_id |  avg(prev.close)   |
+---------------------------+-------------+--------------------+
| January, 04 2016 00:00:00 | 1           | 10.770000457763672 |
| January, 05 2016 00:00:00 | 1           | 10.800000190734863 |
| January, 06 2016 00:00:00 | 1           | 10.673333485921225 |
| January, 07 2016 00:00:00 | 1           | 10.59250020980835  |
| January, 08 2016 00:00:00 | 1           | 10.432000160217285 |
| January, 11 2016 00:00:00 | 1           | 10.40166680018107  |
| January, 12 2016 00:00:00 | 1           | 10.344285828726631 |
| January, 13 2016 00:00:00 | 1           | 10.297500133514404 |
| January, 14 2016 00:00:00 | 1           | 10.2877779006958   |
| January, 04 2016 00:00:00 | 2           | 56.15999984741211  |
| January, 05 2016 00:00:00 | 2           | 56.18499946594238  |
| ..                        | ..          | ..                 |
+---------------------------+-------------+--------------------+

sqlfiddle

<强>参考

sql rolling averages

已修改为使用最后50行

select
rnk_curr.`date`, rnk_curr.security_id, avg(rnk_prev50.close)
from
(
select `date`, security_id,
@row_num := if(@lag = security_id, @row_num + 1,
               if(@lag := security_id, 1, 1)) as row_num
from history 
cross join ( select @row_num := 1, @lag := null ) params
order by security_id, `date`
) rnk_curr
inner join
(
select date, security_id, close,
@row_num := if(@lag = security_id, @row_num + 1,
               if(@lag := security_id, 1, 1)) as row_num
from history 
cross join ( select @row_num := 1, @lag := null ) params
order by security_id, `date`
) rnk_prev50
on  rnk_curr.security_id = rnk_prev50.security_id
and rnk_prev50.row_num between rnk_curr.row_num - 49 and rnk_curr.row_num
group by 1,2
order by 2,1
;

sqlfiddle

注意

if函数是强制正确评估变量的顺序。

MySQL计算N行的移动平均值

1 个答案: