char checkwinner(char ttt[][3]) {
char winner = 0;
for (int p = 0; winner == 0 && p < 2; p++) {
char XO = p == 0 ? 'x' : 'o';
for (int i = 0; winner == 0 && i < 3; i++) {
if (ttt[i][0] == XO && ttt[i][1] == XO && ttt[i][2] == XO)
winner = XO;
else
if (ttt[0][i] == XO && ttt[1][i] == XO && ttt[2][i] == XO)
winner = XO;
}
if (winner == 0 && ttt[0][0] == XO && ttt[1][1] == XO && ttt[2][2] == XO)
winner = XO;
else
if (winner == 0 && ttt[0][2] == XO && ttt[1][1] == XO && ttt[2][0] == XO)
winner = XO;
}
return winner;
}
int main (void) {
char b[3][3] = {{'1', '2', '3'},
{'4', '5', '6'},
{'7', '8', '9'}};
int turn = 0, i, j, loc, type, counter = 0;
char XO, AL;
char theChar = 'A';
char junk ='A';
printf("Type in 1 to play with AL, or 2 to play with another human\n");
scanf("%d", &type);
while (turn <= 9) {
char winner = checkwinner(b);
if (winner == 'x' || winner == 'o') {
printf("%c has won! You get 100 million DOGECOINS! Just enter your debt card information to our website, as well as your checking account and social security number. Go to www.THIS_IS_NOT_A_SCAM.com to get your dogecoins today!\n", winner);
return (0);
} else
if (((b[0][0] == 'x') || (b[0][0] == 'o'))
&& ((b[0][1] == 'x') || (b[0][1] == 'o'))
&& ((b[0][2] == 'x') || (b[0][2] == 'o'))
&& ((b[1][0] == 'x') || (b[1][0] == 'o'))
&& ((b[1][1] == 'x') || (b[1][1] == 'o'))
&& ((b[1][2] == 'x') || (b[1][2] == 'o'))
&& ((b[2][0] == 'x') || (b[2][0] == 'o'))
&& ((b[2][1] == 'x') || (b[2][1] == 'o'))
&& ((b[2][2] == 'x') || (b[2][2] == 'o'))) {
printf("This is a tie.\n");
return (0);
} //<---- missing brace!
if (type == 1) {
counter = counter + 1;
if (counter == 1) { XO = 'x'; }
if (counter == 2) { XO = 'o'; }
if (counter == 3) { XO = 'x'; }
if (counter == 4) { XO = 'o'; }
if (counter == 5) { XO = 'x'; }
if (counter == 6) { XO = 'o'; }
if (counter == 7) { XO = 'x'; }
if (counter == 8) { XO = 'o'; }
if (counter == 9) { XO = 'x'; }
}
if (type == 2) {
XO = 'x';
AL = 'o';
for (i = 0; i < 3; i++) {
for (j = 0; j < 3; j++) {
b[i][j] = AL;
printArray(b);
}
}
}
theChar = getchar();
putchar(theChar);
printf("Enter number: ");
scanf("%d", &loc);
j = (loc - 1) % 3;
i = (loc - 1) / 3;
if ((b[i][j] == 'x') || (b[i][j] == 'o')) {
printf("That spot has been taken!\n");
return (0);
}
putchar('\n');
junk = getchar();
b[i][j] = XO;
printArray(b);
}
}
void printArray(char thearray[3][3]) {
int i, j;
for (i = 0; i < 3; i++) {
for (j = 0; j < 3; j++) {
printf("%c ", thearray[i][j]);
}
printf("\n");
}
}
现在我正试图完成AI模式。而不仅仅是找到第一个空白空间并打印单个“空白”。我的游戏打印出9个这样的板子：
o 2 3
4 5 6
7 8 9
o o 3
4 5 6
7 8 9
o o o
4 5 6
7 8 9
o o o
o 5 6
7 8 9
o o o
o o 6
7 8 9
o o o
o o o
7 8 9
o o o
o o o
o 8 9
o o o
o o o
o o 9
o o o
o o o
o o o
如何在打印一个＆＃39; o后让游戏停止，然后让＆＃39; x＆＃39;选择一招？感谢所有帮助。
答案 0 :(得分：0)
找到AL播放位置的代码不正确：
if (type == 2) {
XO = 'x';
AL = 'o';
for (i = 0; i < 3; i++) {
for (j = 0; j < 3; j++) {
b[i][j] = AL;
printArray(b);
}
}
}
您只需在网格上播放每个位置并进行打印！
请改为尝试：
if (type == 2) {
XO = 'x';
AL = 'o';
for (i = 0; i < 3; i++) {
for (j = 0; j < 3; j++) {
if (b[i][j] != 'x' && b[i][j] != 'o') {
b[i][j] = AL;
i = j = 2; /* ugly way to exit the nested loops */
}
}
}
printArray(b);
}
但这种游戏策略很容易被击败！
此外，您忘记增加turn，但如果您这样做，则可以使用简单的if (turn == 9)替换繁琐的测试。
编辑：退出此嵌套循环需要更多逻辑...最好将AL游戏播放移动到单独的功能。此外，您的逻辑存在缺陷：如果type为2而不是1，则让AL播放...
这是一个可以兼顾双方的简化版本：
#include <stdio.h>
char checkwinner(char b[3][3]) {
for (int i = 0; i < 3; i++) {
if (b[i][0] == b[i][1] && b[i][1] == b[i][2])
return b[i][0];
if (b[0][i] == b[1][i] && b[1][i] == b[2][i])
return b[0][i];
}
if ((b[0][0] == b[1][1] && b[1][1] == b[2][2])
|| (b[0][2] == b[1][1] && b[1][1] == b[2][0])) {
return b[1][1];
}
return 0;
}
void printArray(char b[3][3]) {
for (int i = 0; i < 3; i++) {
printf("%c %c %c\n", b[i][0], b[i][1], b[i][2]);
}
printf("\n");
}
void playAl(char b[3][3], char AL) {
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
if (b[i][j] != 'x' && b[i][j] != 'o') {
b[i][j] = AL;
return;
}
}
}
}
int main (void) {
char board[3][3] = {{'1', '2', '3'},
{'4', '5', '6'},
{'7', '8', '9'}};
int turn, i, j, loc, type;
printf("What does AL play? (0:none, 1:x, 2:o, 3:both) ");
scanf("%d", &type);
for (turn = 0;; turn++) {
printArray(board);
char winner = checkwinner(board);
if (winner == 'x' || winner == 'o') {
printf("%c has won! Game over\n", winner);
return 0;
}
if (turn == 9) {
printf("This is a tie.\n");
return 0;
}
char XO = "xo"[turn % 2];
if (type & (1 << (turn % 2))) {
/* AL's turn to play */
playAl(board, XO);
continue;
}
for (;;) {
printf("Enter number: ");
if (scanf("%d", &loc) != 1)
return 1;
j = (loc - 1) % 3;
i = (loc - 1) / 3 % 3;
if (board[i][j] != 'x' && board[i][j] != 'o')
break;
printf("This spot is already taken!, try again\n");
}
board[i][j] = XO;
}
}