Question

我想从一个图中获得两个组最短路径（一对一），定义为adjacency_list具有内部属性（而不是捆绑）

理论上，我可以在两个参考节点dijkstra_shortest_paths和n1上运行n2。如果我创建两个property_maps并按顺序将它们传递给dijkstra_...，我会看到相同地图的两个视图。两者都指向上次运行dijkstra_shortest_paths的结果，因此较旧的结果消失了。我该怎么做才能达到预期的效果？

// Define some property maps
property_map<ugraph_t,edge_weight_t>::type Weight=get(edge_weight,G);
property_map<ugraph_t,vertex_distance_t>::type Dist1=get(vertex_distance,G);
// One line later, I expect this to be mapped to the SPs w.r.t n1
// Run SP on the first node
dijkstra_shortest_paths(G,n1,predecessor_map(Prev1).distance_map(Dist1).weight_map(Weight));
// New property maps
property_map<ugraph_t,vertex_distance_t>::type Dist2(Dist1); // And now to the second set
property_map<ugraph_t,vertex_predecessor_t>::type Prev2(Prev1); //  But no two sets will result... 
// Run SP on the second node
// This will run fine, but I will lose the first SP set (with or without a copy constructor above)
dijkstra_shortest_paths(G,n2,predecessor_map(Prev2).distance_map(Dist2).weight_map(Weight));

结论：如果我没有弄错，可以将property_map视为与迭代器的接口，以便复制property_map毫无意义。解决方案是传递一个自定义容器，即时构建。这个解决方案详见@sehe下面的回答，非常感谢！

注意：这仅适用于顶点容器类型为vecS的情况。使用listS，必须＆＃34;手动＆＃34;复制顶点顶点。

Answer 1

距离图不应该是内部属性。前一个地图也是如此。

它们不是图形的逻辑属性。它们是查询的结果。因此，它们是查询参数组合的属性，包括图形，起始节点等。

如果您想保存内部属性的值，只需按照通常的方式保存它：

std::vector<double> saved_distances(num_vertices(G));
BGL_FORALL_VERTICES(v, G, ugraph_t)
    saved_distances.push_back(Dist1[v]);

解决方法

复制地图的解决方法：

<强> Live On Coliru

#include <boost/graph/adjacency_list.hpp>
#include <boost/graph/properties.hpp>
#include <boost/graph/dijkstra_shortest_paths.hpp>
#include <boost/graph/iteration_macros.hpp>

using namespace boost;

using ugraph_traits = graph_traits<adjacency_list<vecS, vecS, directedS> >;
using ugraph_t = adjacency_list<
      vecS, vecS, directedS, 
      property<vertex_distance_t, double, 
        property<vertex_predecessor_t, ugraph_traits::vertex_descriptor>
      >,
      property<edge_weight_t, double>
    >;

int main() {
    ugraph_t G(10);
    ugraph_t::vertex_descriptor n1 = 0, n2 = 1, v;
    (void) n1;
    (void) n2;
    // ...

    property_map<ugraph_t, edge_weight_t>::type Weight       = get(edge_weight,G);
    property_map<ugraph_t, vertex_distance_t>::type Dist1    = get(vertex_distance,G);
    property_map<ugraph_t, vertex_predecessor_t>::type Prev1 = get(vertex_predecessor,G);

    dijkstra_shortest_paths(G, n1,
             predecessor_map(Prev1)
            .distance_map(Dist1)
            .weight_map(Weight)
        );

    std::vector<double>                      saved_distances(num_vertices(G));
    std::vector<ugraph_t::vertex_descriptor> saved_predecessors(num_vertices(G));

    BGL_FORALL_VERTICES(v, G, ugraph_t) { 
        saved_distances.push_back(Dist1[v]);
        saved_predecessors.push_back(Prev1[v]);
    }

    /*
     * // C++11 style
     * for(auto v : make_iterator_range(vertices(G)))
     *     saved_distances[v] = Dist1[v];
     */

    // Run SP on the second node
    dijkstra_shortest_paths(G,n2,predecessor_map(Prev1).distance_map(Dist1).weight_map(Weight));
}

建议的

我建议将结果贴图分开容器，只留下边缘重量：

<强> Live On Coliru

更好：重构删除重复的代码

所以它变成了

<强> Live On Coliru

#include <boost/graph/adjacency_list.hpp>
#include <boost/graph/dijkstra_shortest_paths.hpp>

using namespace boost;

using ugraph_t = adjacency_list<vecS, vecS, directedS, no_property, property<edge_weight_t, double> >;
using Vertex   = ugraph_t::vertex_descriptor;

struct ShortestPaths {
    ShortestPaths(size_t num_vertices);
    std::vector<double> distances;
    std::vector<Vertex> predecessors;
};

ShortestPaths GetShortestPaths(ugraph_t const& G, Vertex start);

int main() {
    ugraph_t G(10);
    Vertex n1 = 0, n2 = 1;

    ShortestPaths sp1 = GetShortestPaths(G, n1);
    ShortestPaths sp2 = GetShortestPaths(G, n2);
}

// some other cpp file...:
ShortestPaths::ShortestPaths(size_t num_vertices)
    : distances(num_vertices), predecessors(num_vertices)
{ }

ShortestPaths GetShortestPaths(ugraph_t const& G, Vertex start) {
    ShortestPaths result(num_vertices(G));

    dijkstra_shortest_paths(G, start,
             predecessor_map(make_container_vertex_map(result.predecessors, G))
            .distance_map   (make_container_vertex_map(result.distances, G))
            .weight_map     (get(edge_weight, G))
        );

    return result;
}

请注意，不再需要复制结果。实际上，您甚至不需要保留图表以保留查询结果。

如何复制boost :: property_map？

1 个答案:

解决方法

建议的