Question

我在编写将根据当前时间和当天名称执行功能的代码时遇到问题（例如，周日下午4点）。我已经在下面发布了我的代码，顺便说一句，我对此很新。我知道陈述是否是＆＃34;懒惰＆＃34;并且一旦满足一个条件，它就执行该语句并且不执行其余条件。

let date = NSDate()
let calendar = NSCalendar.currentCalendar()
let components = calendar.components([.Day , .Month , .Year], fromDate: date)

let year =  components.year
let month = components.month
let day = components.day

let componentFHM = calendar.components([ .Hour, .Minute, .Second], fromDate: date)
let hour = componentFHM.hour
let minute = componentFHM.minute


let dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "EEEE"
let dayOfWeekString = dateFormatter.stringFromDate(date)
print(dayOfWeekString)



if week[0] == dayOfWeekString {
    if hour > 0 {
        print("hello")
    }
       } else if week[6] == dayOfWeekString {
           print("hello2")
              }else{
    print("Hello3")
}

if hour >= 9{
   // if minute >= 0{
        if minute >= 30{
            if hour <= 18{
                //if minute >= 0{
                    if minute <= 30{
                print("Hello")
        //I would put the function here.


                    }
                }
            }


}else if hour <= 0{
    //if minute >= 0{
        if minute <= 0{
            if hour <= 0{
              //  if minute >= 0{
                    if minute >= 0{
                        print("HelloWorld")


                }
            }
        }

}else{print("Hello Mac")}

Answer 1

您可以使用switch语句：

let calendar = NSCalendar.currentCalendar()
let components = calendar.components([ .Weekday, .Hour, .Minute], fromDate: NSDate())

switch ( components.weekday, components.hour, components.minute )
{
   case ( 1,     7,       30 ) :  print("Sunday 7H30, take a coffee and do you weekly run")
   case ( 2...6, 6,       _  ) :  print("Weekdays, between 6 and 7 AM, get ready to work")
   case ( 6,     17...23, _  ) :  print("TGIF Party !!!")  
   default : break
}

我如何执行相对于时间的函数？

1 个答案: