Question

我有一个需要不断向上移动的矩形，但也是全局声明的，所以我可以在多个地方调用它：

   var obstacle = SKNode!

  override func didMoveToView {
     obstacle = rectangle()
    }


  func rectangle() -> SKNode {
   let rect = SKSpriteNode(imageNamed: "Rectangle@x2")
    rect.size = CGSizeMake(30, 30)

    rect.position = CGPointMake(210, -250)
    rect.physicsBody?.categoryBitMask = PhysicsCatagory.littleRect
   rect.physicsBody?.contactTestBitMask = PhysicsCatagory.bigRect
    rect.physicsBody?.collisionBitMask = 0
   rect.physicsBody = SKPhysicsBody(rectangleOfSize: rect.size)
    rect.physicsBody?.dynamic = true
    rect.physicsBody?.affectedByGravity = false
    rect.runAction(
        SKAction.moveByX(0, y: 1200,
            duration: NSTimeInterval(6.5)))

    addChild(rect)
    return rect

}
When I attempt to run it as an action repeating forever like so, i get the error "cannot convert value of type SKNode to argument runBlock" : 

   runAction(SKAction.repeatActionForever(
        SKAction.sequence([
            SKAction.runBlock(rectangle),
            SKAction.waitForDuration(4.0)])))

那么有没有办法为这样设置的函数声明这种动作？先感谢您。

Answer 1

首先，这个var obstacle = SKNode!会产生错误。您应该声明一个隐式解包的可选项，如下所示：

 var obstacle:SKNode!

关于主要问题（不分析代码实际执行的逻辑，）...您正在将SKNode类的实例传递给+runBlock:方法（接受闭包），因此错误。要解决这个问题，你必须传递一个闭包，如下所示：

override func didMoveToView(view: SKView) {

    runAction(SKAction.repeatActionForever(
        SKAction.sequence([
            SKAction.runBlock({[unowned self] in self.rectangle()}),
            SKAction.waitForDuration(4.0)])))
}

使用全局函数永远重复动作

1 个答案: