将导出的文件保存/上传到服务器

时间:2016-01-08 10:02:38

标签: php

我将多个表的导出脚本作为备份添加到.sql文件中。该脚本运行良好但我想在服务器上保存备份的副本!我可以将其作为记录插入,但我不能像以前那样使用move_uploaded_file方法进行照片上传。

这是我的剧本:

<?php 
    //ENTER THE RELEVANT INFO BELOW
    //http://stackoverflow.com/a/31531996/1620626
    $mysqlUserName      = "root";
    $mysqlPassword      = "xxx";
    $mysqlHostName      = "localhost";
    $DbName             = "xxx_db";
    $backup_name        ="mybackup.sql";
    $tables             = array("table1","table2");

   //or add 5th parameter(array) of specific tables:    array("mytable1","mytable2","mytable3") for multiple tables

    Export_Database($mysqlHostName,$mysqlUserName,$mysqlPassword,$DbName,  $tables=false, $backup_name=false );

    function Export_Database($host,$user,$pass,$name,  $tables=false, $backup_name=false )
    {
        $mysqli = new mysqli($host,$user,$pass,$name); 
        $mysqli->select_db($name); 
        $mysqli->query("SET NAMES 'utf8'");

        $queryTables    = $mysqli->query('SHOW TABLES'); 
        while($row = $queryTables->fetch_row()) 
        { 
            $target_tables[] = $row[0]; 
        }   
        if($tables !== false) 
        { 
            $target_tables = array_intersect( $target_tables, $tables); 
        }
        foreach($target_tables as $table)
        {
            $result         =   $mysqli->query('SELECT * FROM '.$table);  
            $fields_amount  =   $result->field_count;  
            $rows_num=$mysqli->affected_rows;     
            $res            =   $mysqli->query('SHOW CREATE TABLE '.$table); 
            $TableMLine     =   $res->fetch_row();
            $content        = (!isset($content) ?  '' : $content) . "\n\n".$TableMLine[1].";\n\n";

            for ($i = 0, $st_counter = 0; $i < $fields_amount;   $i++, $st_counter=0) 
            {
                while($row = $result->fetch_row())  
                { //when started (and every after 100 command cycle):
                    if ($st_counter%100 == 0 || $st_counter == 0 )  
                    {
                            $content .= "\nINSERT INTO ".$table." VALUES";
                    }
                    $content .= "\n(";
                    for($j=0; $j<$fields_amount; $j++)  
                    { 
                        $row[$j] = str_replace("\n","\\n", addslashes($row[$j]) ); 
                        if (isset($row[$j]))
                        {
                            $content .= '"'.$row[$j].'"' ; 
                        }
                        else 
                        {   
                            $content .= '""';
                        }     
                        if ($j<($fields_amount-1))
                        {
                                $content.= ',';
                        }      
                    }
                    $content .=")";
                    //every after 100 command cycle [or at last line] ....p.s. but should be inserted 1 cycle eariler
                    if ( (($st_counter+1)%100==0 && $st_counter!=0) || $st_counter+1==$rows_num) 
                    {   
                        $content .= ";";
                    } 
                    else 
                    {
                        $content .= ",";
                    } 
                    $st_counter=$st_counter+1;
                }
            } $content .="\n\n\n";
        }
        $backup_name = $backup_name ? $backup_name : $name."_(".date('H-i-s')."_".date('d-m-Y').").sql";
        //$backup_name = $backup_name ? $backup_name : $name.".sql";
        header('Content-Type: application/octet-stream');   
        header("Content-Transfer-Encoding: Binary"); 
        header("Content-disposition: attachment; filename=\"".$backup_name."\"");  

        move_uploaded_file($backup_name, 'files/bak/'.$backup_name);
        echo $content; exit;
    }
?>

因此,我希望在用户下载files/bak文件时将导出的文件保存到.sql

2 个答案:

答案 0 :(得分:1)

因此,这段代码将备份文件下载到您的浏览器,因此您的客户端机器,备份安全可靠!

    header('Content-Type: application/octet-stream');   
    header("Content-Transfer-Encoding: Binary"); 
    header("Content-disposition: attachment; filename=\"".$backup_name."\"");  

    echo $content; exit;

但是move_uploaded_file();与通过$ _FILES机制上传文件密切相关,所以不要使用它。

您需要做的只是将$content写入文件,它可以像

一样完成
file_put_contents('files/bak/'.$backup_name, $content);

Link to manual - file-put-contents

因此,脚本尾部的完整代码将是

file_put_contents('files/bak/'.$backup_name, $content);

header('Content-Type: application/octet-stream');   
header("Content-Transfer-Encoding: Binary"); 
header("Content-disposition: attachment; filename=\"".$backup_name."\"");  

echo $content; 
exit;

答案 1 :(得分:0)

感谢@RiggsFolly的帮助。我提出了自己的解决方案:

$bakDir='files/bak/';
if (!is_dir($bakDir) or !is_writable($bakDir)) {
    // Error if directory doesn't exist or isn't writable.
    exit($bakDir." is unwritable");
} elseif (!empty($backup_name)) {
    // Error if the file exists and isn't writable.
    if(file_put_contents($bakDir.$backup_name, $content)){
        echo "<script>alert('Backup successfully');</script>";
    }else{
        echo "<script>alert('Backup failed');</script>";
    }
}