Question

我正在尝试从磁盘上传文件，然后将该文件插入到varbinary db列中。

我似乎无法弄清楚如何插入二进制文件。

我在WPF应用程序中使用C＃和Linq to Sql。

这是我到目前为止所尝试的内容！任何建议或意见将不胜感激。

private void UploadFile()
        {
            DatabaseData.DataClassesDataContext context = new DatabaseData.DataClassesDataContext();
            {
            OpenFileDialog dlgOpen = new OpenFileDialog();
            dlgOpen.Title = "Select file";

            FileData fd = new FileData();
            if (dlgOpen.ShowDialog() ?? false)
            {
                FileStream inStream = File.OpenRead(dlgOpen.FileName);
                //FileStream outStream = File.OpenWrite(dlgOpen.FileName + ".xlsx");
                int b;

                while ((b = inStream.ReadByte()) > -1)
                    // outStream.WriteByte((byte)b);


                    fd.FileId = Guid.NewGuid();
                    //fd.DataFile = inStream;//DataFile is the Varbinary column in the db
                    fd.Title = dlgOpen.FileName;
                    fd.FileExtension = txtExtension.text;

                    context.FileDatas.InsertOnSubmit(fd);
                    context.SubmitChanges();

                    //outStream.Flush();
                    //outStream.Close();
                    inStream.Close();
            }
            }
        }

Answer 1

要修复编译错误，请删除while语句。您正在尝试创建一个新的FileData（），在b > -1之前永远不能使用它。

我不知道代码会在那之后工作，但它会解决这个编译错误。

private void UploadFile()
{
    DatabaseData.DataClassesDataContext context = new DatabaseData.DataClassesDataContext();
    {
        OpenFileDialog dlgOpen = new OpenFileDialog();
        dlgOpen.Title = "Select file";

        if (dlgOpen.ShowDialog() ?? false)
        {
            FileStream inStream = File.OpenRead(dlgOpen.FileName);

            FileData fd = new FileData();
            fd.FileId = Guid.NewGuid();
            fd.DataFile = inStream;
            fd.Title = dlgOpen.FileName;
            fd.FileExtension = txtExtension.text;

            context.FileDatas.InsertOnSubmit(fd);
            context.SubmitChanges();

            inStream.Close();
        }
    }
}

Answer 2

不确定这是否有效，但请尝试此

 if (dlgOpen.ShowDialog() ?? false)
                    {
                        byte[] bytes = System.IO.File.ReadAllBytes(dlgOpen.FileName);

                            fd.FileId = Guid.NewGuid();
                            fd.DataFile = bytes;
                            fd.Title = dlgOpen.FileName;                   
                            context.FileDatas.InsertOnSubmit(fd);
                            context.SubmitChanges();

Answer 3

嗯，您在评论中阅读了我的免责声明。我不能保证这里的任何专业人员都会同意根据您的要求采用的方法。我正在以正确的方式学习C＃，并且有了转换一个有效的非数据库程序的想法。我需要将所有现有数据转换为一个新的数据库来接管存储：

/* Spawned from a button click
...
*/
        //
        // Here I bring in the directory which you'll likely replace with
        // a single file
        //
        string[] files = 
            Directory.GetFiles( 
            @"yourDicectory");

            // 
            // At this point you may disregard my loop if needed
            //
            foreach (string file in files)
            {
                //
                // Here the entire files are read and split
                // Handle your data how you like
                //  
                StreamReader fileReader = new StreamReader( file );
                string lines = fileReader.ReadToEnd();
                string[] entries = lines.Split( ',' );

                // 
                // Here, omitted, I declare variables of types to insert "holders" 
                // Every CSV has to go to a corresponding holder of the 
                // the appropriate type (i.e., DateTime, decimal(money), or yourType)
                //

                SqlCeConnection con = new SqlCeConnection( "Data Source = YourDataSource.sdf" );
                con.Open();
                SqlCeCommand cmd  = con.CreateCommand();

                //
                // The insert command that takes the parsed values - value1, value2, ...
                // which are the named and omitted declarations from above
                // You're providing a signature of the table you're inserting into
                // 
                cmd.CommandText = "INSERT INTO YourTable ([Column1], [Column2], [Column3], ... , [Column(n)]) VALUES (value1, value2, value3, ... , value(n))";

                //
                // Here, omitted, I parse and convert the values and store them in the holders
                //

                // Now execute and catch if needed
                    try
                    {
                        cmd.ExecuteNonQuery();
                    }
                    catch( SqlCeException sqle )
                    {
                        myTextbox.Text += sqle.Errors.ToString() + "\n";
                    }
                }
                //
                // Update my view - May not apply
                //
                myGridView1.Update();
                con.Close();
            }
/* Do whatever else you'd like ... */

Answer 4

File operations in C# (my blog link will help you)

上传文件并保存到数据库

4 个答案: