Question

我做了一个简单的猜数字程序，在我学习python的过程中！洛尔

然而，计算机不会确认用户的猜测是正确的，并且它总是会变为“不正确”，即使计算机编号显示为用户猜测。我的代码似乎是正确的，所以我不知所措。任何帮助表示赞赏！

def randomNumGen():
    userGuess = input('The Computer has thought of a number between 1-5, deposit    your guess now!: ')

    if finalValue == userGuess:
        print("You've guessed correctly!, Very lucky you are!")

    else:
        print("You're guess was incorrect, try again please")
        print("The computer's guess was",finalValue)
        main()

编辑：

输出看起来像这样，这解释了这里显而易见的问题：

>The Computer has thought of a number between 1-5, deposit your guess now!: 2
>You're guess was was incorrect 
>The computer's guess was 2

所以当'计算机'被给出时，它将无法识别正确的猜测。

Answer 1

最有可能finalValue是一个整数，而来自input()的输入将是一个字符串。在比较之前，你应该把它们变成字符串，或者两者都变成整数。

要将整数转换为字符串，您只需执行以下操作：

my_string = str(my_integer)

这将采用名为my_integer的整数并返回一个字符串，该字符串将被指定为my_string

def randomNumGen():
    userGuess = input('The Computer has thought of a number between 1-5, deposit    your guess now!: ')

    if str(finalValue) == userGuess:
        print("You've guessed correctly!, Very lucky you are!")

    else:
        print("You're guess was incorrect, try again please")
        print("The computer's guess was",finalValue)
        main()

这是我能看到的最简单的改变，可以使这项工作成功。注意这一行：

if str(finalValue) == userGuess:

我正在将finalValue强制转换为与userGuess的字符串进行比较。

Answer 2

我认为问题在于，当需要将输入识别为整数时，您的输入将被处理为字符串。试试这个：

def randomNumGen():
userGuess = input('The Computer has thought of a number between 1-5,     deposit    your guess now!: ')
userGuess = int(userGuess)

if finalValue == userGuess:
    print("You've guessed correctly!, Very lucky you are!")

else:
    print("You're guess was incorrect, try again please")
    print("The computer's guess was",finalValue)
    main()

我的基本'猜数字程序'，它不会承认'对计算机数字的正确猜测'

2 个答案: