Question

我编写了一个类，我将一个Light声明为属性。在构造函数中，我在使用之前实例化Light对象，但是在实例化之后的行（NodeLight.type = LightType.Spot;）处得到了空引用异常。

 using UnityEngine;
 using System.Collections;

 public class Node{

     public bool walkable;
     public Vector3 worldPosition;
     public bool Selected;
     public Light NodeLight;

     public Node(bool _walkable, Vector3 _worldPos) {
         Selected = false;
         walkable = _walkable;
         worldPosition = _worldPos;
         NodeLight = new Light();
         NodeLight.type = LightType.Spot;
         NodeLight.transform.position = new Vector3(worldPosition.x, worldPosition.y + 3f, worldPosition.z);
         NodeLight.enabled = false;
     }
 }

感谢您的帮助

Answer 1

Light是Component，因此它应该存在于GameObject内。

从Unity Docs：

查看此示例

public class ExampleClass : MonoBehaviour {
    void Start() {
        GameObject lightGameObject = new GameObject("The Light");
        Light lightComp = lightGameObject.AddComponent<Light>();
        lightComp.color = Color.blue;
        lightGameObject.transform.position = new Vector3(0, 5, 0);
    }
}

尝试这种方法，或尝试将NodeLight添加为Component的{{1}}，然后更改其位置，而不是单个GameObject组件＆＃39;第

实例化轻型游戏对象后出现空引用异常

1 个答案: