Question

我有一个文本文件的输出，如下所示。我想将someItems数组的所有内容放在一行之下。因此，每一行都会有一个新的someItems数组的内容。例如：

"someItems": [
{
  "someId": "MountSomers-showtime.com-ETTI0000000000000003-1452005472058",
  "source": "MountSomers",
  "sourceAssetId": "9",
  "title": "Pk_3",
  "ppp": "12",
  "expirationDate": "2016-01-06T14:51:12Z"
},    {
  "someId": "MountSomers-ericsson.com- ETTI0000000000000005-1452005472058",
  "source": "MountSomers",
  "sourceAssetId": "12",
  "title": "Pk_5",
  "ppp": "12",
  "expirationDate": "2016-01-06T14:51:12Z"
}  ]
"someItems": [
{
  "someId": "MountSomers-hbo.com-ETTI0000000000000002-1452005472058",
  "source": "MountSomers",
  "sourceAssetId": "7",
  "title": "Pk_2",
  "ppp": "12",
  "expirationDate": "2016-01-06T14:51:12Z"
},    {
  "someId": "MountSomers-showtime.com-ETTI0000000000000003-1452005472058",
  "source": "MountSomers",
  "sourceAssetId": "9",
  "title": "Pk_3",
  "ppp": "12",
  "expirationDate": "2016-01-06T14:51:12Z"
},    {
  "someId": "MountSomers-ericsson.com-ETTI0000000000000005-1452005472058",
  "source": "MountSomers",
  "sourceAssetId": "12",
  "title": "Pk_5",
  "ppp": "12",
  "expirationDate": "2016-01-06T14:51:12Z"
}  ]

会变成

"someItems": [ ..... ]
"someItems": [ ..... ]

我有以下

cat file | | awk '/^"someItems": [/{p=1}/^]/{p=0} {if(p)printf "%s",$0;else printf "%s%s\n",(NR==1?"":RS),$0}'

但它没有做我想要的......

Answer 1

由于输入仅在外层包含括号[]，因此解决方案非常简单：

awk '{gsub("\n","", $0)}1' RS=']\n' file

我使用]\n作为输入记录分隔符。这为您提供了"someItems: ..."到结束]之间$0的整个部分。 gsub()只是替换换行符。 1打印（修改过的）记录。

您还可以使用sed：

sed '/\[/{:a;N;/]/!ba;s/\n//g}' file

我将在多行版本中解释它：

script.sed ：

# Address. Matches a line containing the opening [
/\[/ { # Start of block

    # Define a label 'a'
    :a

    # Read a new line and append it to the pattern buffer
    N

    # If the pattern buffer doens't contain the closing ]
    # jump back to label 'a'
    /]/!ba

    # Replace all newlines once the closing bracket appeared
    # Since we don't jump back to 'a' in this case, this means we'll
    # leave the block and start a new cycle.
    s/\n//g

} # End of block

Answer 2

$ awk '/^"someItems":/ && f { printf "\n" } { printf $0; f=1 } END { printf "\n" }' file.txt
"someItems": [{  "someId": "MountSomers-showtime.com-ETTI0000000000000003-1452005472058",  "source": "MountSomers",  "sourceAssetId": "9",  "title": "Pk_3",  "ppp": "12",  "expirationDate": "2016-01-06T14:51:12Z"},    {  "someId": "MountSomers-ericsson.com- ETTI0000000000000005-1452005472058",  "source": "MountSomers",  "sourceAssetId": "12",  "title": "Pk_5",  "ppp": "12",  "expirationDate": "2016-01-06T14:51:12Z"}  ]
"someItems": [{  "someId": "MountSomers-hbo.com-ETTI0000000000000002-1452005472058",  "source": "MountSomers",  "sourceAssetId": "7",  "title": "Pk_2",  "ppp": "12",  "expirationDate": "2016-01-06T14:51:12Z"},    {  "someId": "MountSomers-showtime.com-ETTI0000000000000003-1452005472058",  "source": "MountSomers",  "sourceAssetId": "9",  "title": "Pk_3",  "ppp": "12",  "expirationDate": "2016-01-06T14:51:12Z"},    {  "someId": "MountSomers-ericsson.com-ETTI0000000000000005-1452005472058",  "source": "MountSomers",  "sourceAssetId": "12",  "title": "Pk_5",  "ppp": "12",  "expirationDate": "2016-01-06T14:51:12Z"}  ]
$

打印每一行没有尾随换行符。从第二次出现开始，在每个"someItems"之前放置一个前导换行符。在最后打印换行符以保持优雅。

替换两个单词之间的换行符

2 个答案: