Question

我有一个看起来像的文件：

name: charles
key1: how
are
you?
name: erika
key2: I'm
fine,
thanks
name: ...

如何删除“key \ d +”和“name：”之间的新行？它应该是这样的：

name: charles
key1: how are you?
name: erika
key2: I'm fine, thanks
name: ...

我正在尝试使用sed或awk但没有任何成功。有没有办法清理这些线？

有没有办法删除“key \ d +：”和“\ w +：”之间的换行符？

Answer 1

这样的事情？

kent$  awk '/^key.:/{p=1}/^name:/{p=0}
            {if(p)printf "%s",$0;else printf "%s%s\n", (NR==1?"":RS),$0}' file
name: charles
key1: howareyou?
name: erika
key2: I'mfine,thanks
name: ...

处理空格：

awk '/^key.:/{p=1}/^name:/{p=0}
    {if(p)printf "%s%s",(/^key.:/?"":" "),$0;
    else printf "%s%s\n", (NR==1?"":RS),$0}' file

输出：

name: charles
key1: how are you?
name: erika
key2: I'm fine, thanks
name: ...

Answer 2

这可能适合你（GNU sed）：

sed ':a;$!N;/\n.*:/!s/\n/ /;ta;P;D' file

如果第二行没有以关键字:开头，请在模式空间中保留两行并从第一行中删除换行符。当关键字和:遇到打印然后删除第一行时。

Answer 3

替代awk解决方案。

awk '
  {
    if      (NR == 1)                s = ""
    else if ($1 ~ /^[[:alnum:]]+:$/) s = RS
    else                             s = " "
    printf "%s%s", s, $0
  }
  END {print ""}
'<<EOF
name: charles
key1: how
are
you?
name: erika
key2: I'm
fine,
thanks
EOF
name: charles
key1: how are you?
name: erika
key2: I'm fine, thanks

Answer 4

以下作品，但表现显然不是最好的：

cat file.txt | while read x;do echo "$x" | grep -q ':' && echo; echo -ne "$x "; done | sed -n 's/ $//p'

name: charles
key1: how are you?
name: erika
key2: I'm fine, thanks
name: ...

删除两个单词之间的换行符

4 个答案: